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bearhunter [10]
3 years ago
14

Tendons are strong elastic fibers that attach muscles to bones. To a reasonable approximation, they obey Hooke's law. In laborat

ory tests on a particular tendon, it was found that, when a 251 g object was hung from it, the tendon stretched 1.23 cm .Find the force constant of this tendon.
Physics
1 answer:
meriva3 years ago
5 0

Answer:

k = 200 N/m

Explanation:

given,

mass of the object  = 251 g

                                = 251 x 10⁻³ Kg = 0.251 Kg

distance of tendon stretch = x = 1.23 cm

                                            = 1.23 x 10⁻² = 0.0123 m

using the formula

F = k  x

where

k is the force constant of the tendon

F = m g

F = 0.251 x 9.8 = 2.4598 N

2.4598 = k x 0.0123

k = 199.98 N/m

k = 200 N/m

hence, force constant of the tendon is approximately equal to 200 N/m

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each resistor is 540 Ω

Explanation:

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Period = 1/17 seconds

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<em>Given the speed of sound wave as 340 m/s </em>

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