Answer:
<em>I must travel with a speed of 2.97 x 10^8 m/s</em>
Explanation:
Sine the spacecraft flies at the same speed in the to and fro distance of the journey, then the time taken will be 6 months plus 6 months
Time that elapses on the spacecraft = 1 year
On earth the people have advanced 120 yrs
According to relativity, the time contraction on the spacecraft is gotten from
= 
where
is the time that elapses on the spacecraft = 120 years
= time here on Earth = 1 year
is the ratio v/c
where
v is the speed of the spacecraft = ?
c is the speed of light = 3 x 10^8 m/s
substituting values, we have
120 = 1/
squaring both sides of the equation, we have
14400 = 1/
14400 - 14400
= 1
14400 - 1 = 14400
14399 = 14400
= 14399/14400 = 0.99
= 0.99
substitute β = v/c
v/c = 0.99
but c = 3 x 10^8 m/s
v = 0.99c = 0.99 x 3 x 10^8 = <em>2.97 x 10^8 m/s</em>
Answer:
The time taken is 84 seconds, please give the brainliest award would be much appreciated.
Answer: final Displacement = 0 km, total distance covered =7 km
Explanation:
Given the following :
From home to library = 1.3 km East
Library to music store = 0.68km East
Music store to friend's house = 1.1km North
Friend's house to grocery store = 0.42 km North
Displacement is the net change in distance traveled.
Eastward distance :
To = (1.3 + 0.68)km = 1.98km East
Fro = (0.68 + 1.3)km = 1.98 km East
Δ distance = (1.98 - 1.98) = 0
Northward direction:
To = (1.1 + 0.42)km = 1.52km north
Fro = (0.42 + 1.1)km = 1.52km North
Δ distance = (1.98 - 1.98) = 0
Hence final Displacement = 0
Total distance covered = 2 × (1.3 + 0.68 + 1.1 + 0.42) = 2 × 3.5
= 7km
Answer:
5.5 km
Explanation:
First, we convert the distance from km/h to m/s
910 * 1000/3600
= 252.78 m/s
Now, we use the formula v²/r = gtanθ to get our needed radius
making r the subject of the formula, we have
r = v²/gtanθ, where
r = radius of curvature needed
g = acceleration due to gravity
θ = angle of banking
r = 252.78² / (9.8 * tan 50)
r = 63897.73 / (9.8 * 1.19)
r = 63897.73 / 11.662
r = 5479 m or 5.5 km
Thus, we conclude that the minimum curvature radius needed for the turn is 5.5 km
Answer:
The answer is 218
Explanation:
Weight = mass * gravitational acceleration
weight is represented by F
F = 25kg (8.7)
(I'm pretty sure that you don't have to include the meters per second/per second thing)
