Most commonly the answer is A, the sun. A nebula is a nursery for stars. The Sun itself was created in a nebula. Also,you do not need college physics to understand this question
Answer:
when there is no water in the atmosphere or when no drops are formed there is no rainbow..
he hydrogen transition lines would be missing in the visible range, the RED region
Explanation:
The sunlight that reaches the Earth is scattered by the atmosphere and radiated, as the atmosphere has mainly nitrogen, the radiated light is blue, this light does not produce a rainbow.
The sunlight must reach a drop of water that disperses the colors according to the refractive index of the water and in this way produces a rainbow, so when there is no water in the atmosphere or when no drops are formed there is no rainbow..
If the atmosphere were composed of Hydrogen, the hydrogen transition lines would be missing in the visible range, this corresponds to the so-called Balmer series and they are in the RED light region.
Answer:
A. 88,200 J
Explanation:
Given data,
The mass of the crate, m = 200 kg
The height of the shipping container, h = 45 m
The gravitational of a body is possessed by the body due to the virtue of its position.
The formula for gravitational potential energy is,
P.E = mgh joules
Substituting the values
P.E = 200 x 9.8 x 45
= 88,200 J
Hence, the gravitational potential energy of the crate is, P.E = 88,200 J
Answer:
True
Explanation:
Because in atom the negative charge become lose or gain.
<span>2. For each pair of substances, identify the substance that will take more energy to heat from 20C to 100C and explain why. Specific heat for water- 4180 J/kg°C. Specific Heat for silver- 235 J/kg°C. Specific heat for iron-450 J/kg°C.
a. 30 g of water vs. 300 g of water
Q = mcp</span>ΔT
Q(water) = (0.03kg)(4180 J/kg°C)(100-20)
<span>Q(water) = 10,032 J
</span>Q(water) = (0.3kg)(4180 J/kg°C)(100-20)
Q(water) = 100,320 J
<span>300g of water takes mroe heat than 30g of water.
b. 500 g of iron vs. 500 g of silver
</span>Q = mcpΔT
Q(iron) = (0.5g)(-450 J/kg°C)(100-20)
Q(iron) = -18,000J
Q(silver) = (.5g)(-235 J/kg°C)(100-20)
Q(silver) = -9,400J
Iron gives off more heat than silver