Answer:
speed of light simulating traveling at the speed of light. Speed of light, speed at which light waves propagate through different materials. In particular, the value for the speed of light in a vacuum is now defined as exactly 299,792,458 metres per second
The speed of sound is the distance travelled per unit of time by a sound wave as it propagates through an elastic medium
At some time during her drive she backed up with a substantial negative. ( backwards) acceleration. Since the pocket book is not physically connected to the seat it is free to move. Upon rapid negative acceleration the pocket book remains in its position while the car accelerates backwards away from it. this demonstrates Newtons 1st law of motion. The first law is the law of inertia. Which states, an object at rest. ( pocketbook) will remain at rest and an object in motion will continue in motion at constant velocity, unless acted upon by some outside force to change its motion.
Answer:
When the radius is doubled, its speed will be 42.42 km/h.
Explanation:
Given that,
The maximum speed around a level curve is 30 km/h = 8.34 m/s
We need to find the maximum speed around a curve with twice the radius. The maximum speed of the object is given by :
............(1)
If radius is doubled, r' = 2r
The maximum speed is given by :
..........(2)
Dividing equation (1) and (2) we get :
v' = 42.42 km/h
So, when the radius is doubled, its speed will be 42.42 km/h. Hence, this is the required solution.
<span>Improved Heart Health
</span><span>Increased Metabolism
</span><span>Improved Hormonal Profile
</span><span>Improved Recovery Ability
</span><span>Management Of Diabetes</span>
Using trigonometric ratios we can get the distance;
For the first car; The distance from the point on the highway below the plane
tan = opp/adj
tan(36°) = 5150/x
0.727 = 5150/x
0.727x = 5150
x = 7088.37
For the second car we also use tangent; the distance from the point on the highway below the plane will be;
tan(56°) = 5150/y
1.483 = 5150/y
1.483y = 5150
y= 3473.72
The we can add the two distances to get how far apart the cars are;
7088.37 + 3473.72 = 10562.09 feet.
= 10562.09 ft
