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3 years ago

A ball is dropped from rest on a cliff what is the speed of the ball 5 seconds later

Physics

1 answer:

diamong [38]3 years ago

4 0

Answer:

The velocity of the ball after 5 seconds will be 49 m/s

Explanation:

v = final velocity

u = initial velocity

g = acceleration due to gravity

t = time

Initial velocity of the ball = 0 (As the ball is dropped from rest )

Acceleration due to gravity = 9.8 m/s

Time taken = 5 sec

As the acceleration due to gravity is constant in both the cases we can use the equations of motion in order to solve this question

Part I :- As we already know the values of u,g,ant t we can use the first equation of motion in order to find v

Part II :- As we know the values of u, t , g we can use the second equation of motion in order to find s.

Velocity of the ball after 5 seconds

Distance covered by the ball in 5 sec

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Answer:

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Explanation:

Data;

Mass = 925kg

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a) = work = force * distance

But force = mass * acceleration

Force = 925 * 9.8 = 9065N

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a = v² / 2s

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v² = 558.6

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258352.5 = ½ * 8.0*10⁴ * x²

(2 * 258352.5) = 8.0*10⁴x²

516705 = 8.0*10⁴x²

X² = 516705 / 8.0*10⁴

X² = 6.46

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Answer:

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