1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
AlladinOne [14]
3 years ago
13

Select the correct answer.

Engineering
1 answer:
neonofarm [45]3 years ago
5 0

Answer:A 1.

Explanation:

You might be interested in
Motorcycles are extremely hard to see if they are _______. powered by quiet motors approaching from the side driving on the shou
Assoli18 [71]

Answer: uve earned 5 b point for helping us

Explanation:well know I'm not helping u

7 0
3 years ago
The hydrofoil boat has an A-36 steel propeller shaft that is 100 ft long. It is connected to an in-line diesel engine that deliv
Nataliya [291]

The question is incomplete. The complete question is :

The hydrofoil boat has an A-36 steel propeller shaft that is 100 ft long. It is connected to an in-line diesel engine that delivers a maximum power of 2590 hp and causes the shaft to rotate at 1700 rpm . If the outer diameter of the shaft is 8 in. and the wall thickness is $\frac{3}{8}$  in.

A) Determine the maximum shear stress developed in the shaft.

$\tau_{max}$ = ?

B) Also, what is the "wind up," or angle of twist in the shaft at full power?

$ \phi $ = ?

Solution :

Given :

Angular speed, ω = 1700 rpm

                              $ = 1700 \frac{\text{rev}}{\text{min}}\left(\frac{2 \pi \text{ rad}}{\text{rev}}\right) \frac{1 \text{ min}}{60 \ \text{s}}$

                              $= 56.67 \pi \text{ rad/s}$

Power $= 2590 \text{ hp} \left( \frac{550 \text{ ft. lb/s}}{1 \text{ hp}}\right)$

          = 1424500 ft. lb/s

Torque, $T = \frac{P}{\omega}$

                 $=\frac{1424500}{56.67 \pi}$

                 = 8001.27 lb.ft

A). Therefore, maximum shear stress is given by :

Applying the torsion formula

$\tau_{max} = \frac{T_c}{J}$

        $=\frac{8001.27 \times 12 \times 4}{\frac{\pi}{2}\left(4^2 - 3.625^4 \right)}$

      = 2.93 ksi

B). Angle of twist :

     $\phi = \frac{TL}{JG}$

         $=\frac{8001.27 \times 12 \times 100 \times 12}{\frac{\pi}{2}\left(4^4 - 3.625^4\right) \times 11 \times 10^3}$

         = 0.08002 rad

         = 4.58°

6 0
3 years ago
A gear box’s shaft is made of a hollow circular steel tube with allowable yield stress equal to σa????????o???? . The shaft is l
Leni [432]

Answer:

See explaination

Explanation:

The failure theory asserts that Material failure theory is the science of predicting the conditions under which solid materials fail under the action of external loads. The failure of a material is usually classified into brittle failure or ductile failure.

See attachment for the step by step solution.

3 0
4 years ago
Calculate the volume of a hydraulic accumulator capable of delivering 5 liters of oil between 180 and 80 bar, using as a preload
Vinil7 [7]

Answer:

1) V_o = 10 liters

2) V_o = 12.26 liters

Explanation:

For isothermal process n =1

V_o =\frac{\Delta V}{(\frac{p_o}{p_1})^{1/n} -(\frac{p_o}{p_2})^{1/n}}

V_o  = \frac{5}{[\frac{72}{80}]^{1/1} -[\frac{72}{180}]^{1/1}}

V_o = 10 liters

calculate pressure ratio to determine correction factor

\frac{p_2}{p_1} =\frac{180}{80} = 2.25

correction factor for calculate dpressure ration  for isothermal process is

c1 = 1.03

actual \ volume = c1\times 10 = 10.3 liters

b) for adiabatic process

n =1.4

volume of hydraulic accumulator is given as

V_o =\frac{\Delta V}{[\frac{p_o}{p_1}]^{1/n} -[\frac{p_o}{p_2}]^{1/n}}

V_o  = \frac{5}{[\frac{72}{80}]^{1/1.4} -[\frac{72}{180}]^{1/1.4}}

V_o = 12.26 liters

calculate pressure ratio to determine correction factor

\frac{p_2}{p_1} =\frac{180}{80} = 2.25

correction factor for calculate dpressure ration  for isothermal process is

c1 = 1.15

actual \volume = c1\times 10 = 11.5 liters

8 0
3 years ago
The pressure and temperature at the beginning of compression of a cold air-standard Diesel cycle are 100 kPa and 300K, respectiv
hram777 [196]

Answer:

Cut off ratio=2.38

Explanation:

Given that

T_1=300K

P_1=100KPa

P_2=P_3=7200KPa

T_3=2250K

Lets take T_1 is the temperature at the end of compression process

For air γ=1.4

\dfrac{T_2}{T_1}=\left(\dfrac{P_2}{P_1}\right)^{\dfrac{\gamma -1}{\gamma}}

\dfrac{T_2}{300}=\left(\dfrac{7200}{100}\right)^{\dfrac{1.4-1}{1.4}}

T_2=1070K

At constant pressure

\dfrac{T_3}{T_2}=\dfrac{V_3}{V_2}

\dfrac{2550}{1070}=\dfrac{V_3}{V_2}

\dfrac{V_3}{V_2}=2.83

So cut off ratio

cut\ off\ ratio =\dfrac{V_3}{V_2}

Cut off ratio=2.38

6 0
4 years ago
Other questions:
  • How do I quickly learn javascript?
    8·1 answer
  • Physical strength and dexterity for operating tools are most important for
    5·1 answer
  • Compute the estimated actual endurance strength (Sn) for SAE 3140 OQT 1000 steel bar with a rectangular cross section of w-30 mm
    6·1 answer
  • What do you enjoy most and least about engineering?
    15·2 answers
  • Calculate the convective heat-transfer coefficient for water flowing in a round pipe with an inner diameter of 3.0 cm. The water
    8·1 answer
  • A piece of corroded metal alloy plate was found in a submerged ocean vessel. It was estimated that the original area of the plat
    8·1 answer
  • What is the name for a program based on the way your brain works?
    13·2 answers
  • WHICH OF THIS PLS FAST!!!
    5·1 answer
  • Arm coverings can NOT protect you from cuts or puncture wounds. Is this statement<br> TRUE or FALSE?
    6·1 answer
  • A plate of width 84mm and thickness 10mm is to be welded to another plate by means of double parallel fillets. The plates are su
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!