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avanturin [10]
3 years ago
14

NEED REAL ANSWER NICE AMOUNT OF POINTS AND BRAINLY

Biology
2 answers:
labwork [276]3 years ago
7 0

Answer:

The compound boron trifluoride, BF3, does not have non-bonding valence electrons and  The following diagram shows four possible orientations of the O-H bonds.  but the other configurations would give two different CH2Cl2 compounds. structure consisting of a simple chain of four carbon atoms, CH3CH2CH2CH3.

Explanation:

take notes

Ksenya-84 [330]3 years ago
3 0

Answer:

  ch3 is a asid compound an has some propertys of the other two but it is an asid

Explanation:

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Ecosystem productivity is principally limited by _______.
marusya05 [52]
 sunlight and nutrient availability
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In a genetic cross between aabbccddee and aabbccddee what fraction of the offspring will be homozygous dominant for all five gen
aniked [119]

Answer:

None

Explanation:

The desired homozygous dominant genotype is AABBCCDDEE. To have an offspring with genotype "AABBCCDDEE", at least one copy of the dominant alleles for the genetic loci should be present in either of the parent. However, both the parents are homozygous recessive for all the five mentioned genetic loci and therefore, cannot have a progeny with homozygous dominant genotype "AABBCCDDEE". All the progeny of a cross between the two parents each with genotype "aabbccddee" would have homozygous recessive for all the give loci.

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3 years ago
The group that has elements with the outer energy level filled is called the.
Nezavi [6.7K]
The Noble Gases. The Noble Gases is a(n) group on the periodic table of elements that contains elements that have full valence electron shells. Because of this, the Noble Gases do not react with any other elements.
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2 years ago
Electrical energy can produce many other types of energy.
dolphi86 [110]

Answer:

Heat energy is the answer

Explanation:

I hope that answers your question.

6 0
3 years ago
What is the 95% CI for data set 2?
vesna_86 [32]

Answer: 20 ± 11.32

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For the data set 2, z-value for 95% confidence interval is z = 1.96

Formula to calculate CI is

x ± z\frac{s}{\sqrt{n} }

where

x is mean

z is z-value

s is standard deviation

n is the sample number

Then:

20 ± 1.96\frac{10}{\sqrt{3} }

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20 ± \frac{19.6}{1.7320}

20 ± 11.32

The 95% CI is 20 ± 11.32, which means there is a 95% certainty the true value is between 8.68 and 31.32.

8 0
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