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Gennadij [26K]
3 years ago
12

A unique type of basketball is played on the planet zarth. During the game, a player flies above the basket and drops the ball i

n from a height of 10 m. If the ball takes 5.0 s to fall, find the acceleration due to gravity on zarth.
Physics
2 answers:
pickupchik [31]3 years ago
8 0

Answer:

The acceleration due to gravity on zarth = 0.8m/s^2

Explanation:

The acceleration due to gravity on earth = 9.8m/s^2

We know that time taken(t) by an object to fall a distance (d) is given by

t = \sqrt{ (2d/g)}

We are given the height from which the ball is dropped = 10m and the time taken by the ball to fall = 5.0s

So, substituting the given values

d = height of dropping the ball = 10m, t = 5.0 s

i.e. time taken for fall ,in the equation,

t^2 = 2d/g

g= 20/5^2 = 20/25 = 0.8

Therefore (g) = 0.8m/s^2 which gives the acceleration due to gravity on planet Zarth.

Murljashka [212]3 years ago
6 0

Answer:

0.8 m/s^2

Explanation:

The motion of an object in free fall is a uniformly accelerated motion, so we can analyze it using the following suvat equation:

s=ut+\frac{1}{2}gt^2

where, taking downward as positive direction:

s is the vertical displacement

u is the initial velocity

t is the time of flight

g is the acceleration of gravity

For the ball dropped in this problem,

s = 10 m

t = 5.0 s

u = 0

Therefore, solving the equation for g, we find the acceleration due to gravity:

g=\frac{2s}{t^2}=\frac{2(10)}{5^2}=0.8 m/s^2

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s344n2d4d5 [400]

Answer:

Skeletal muscle cells

Explanation:

Skeletal muscle cells are long, cylindrical, and striated. They are multi-nucleated meaning that they have more than one nucleus. This is because they are formed from the fusion of embryonic myoblasts.

pls mark me the brainliest

7 0
2 years ago
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The coefficient of kinetic friction between an object and the surface upon which it is sliding is 0. 10. The mass of the object
lilavasa [31]

The force of friction is 78.4 N

What is force of friction?

Frictional force is the force created when two surfaces come into contact and slide against each other. it is given by the equation:

F_{f} = μ * F_{n}

where,

F_{f} = force of friction

μ = coefficient of friction

F_{n} = normal force

Given,

μ = 0.10,  m = 8.0 kg

We know,

F_{n} = mg

F_{n} = 8.0 * 9.8\\\\ F_{n} = 78.4 N

Subsituing the values in equation:

F_{f} = μ * F_{n}

F_{f} = 0.10 * 78.4 \\\\F_{f} = 7.84 N

The force of friction is 78.4 N.

To know more about force of friction, check out:

brainly.com/question/24386803

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4 0
1 year ago
A sphere of mass 40kg is attaracted by a second sphere of mass 15 kg when their centers are 20 cm apart with a force of 0.1mg-wt
ser-zykov [4K]
<span>gravitational force = 0.1 mg-wt. = 0.1 * 10^-6 * 9.8 N = Gm1m2/r^2
 m1 = 40 kg m2 =15 kg and r = 0.2 m
 Put in and find G</span>
3 0
3 years ago
If rho(x,y) is the density of a wire (mass per unit length), then
lidiya [134]

Answer:

See description

Explanation:

With the given information we have:

x(t) = 1 + cos(t)\\ y(t)=sin(t)\\ \rho(x,y) = 3x

the interval is [0,\pi ]

now the mass m has the given expression:

m = \int \rho(x,y) dS

we will use the formula for a line integral and let:

dS=\sqrt{x'(t)^2 + y'(t)^2}=\sqrt{cos(t)^2 + sin(t)^2}dt=dt

therefore we have:

m=\int \rho(x,y)dS=\int\limits^\pi_0 {3*x}dS=\int\limits^\pi _0{3*(1+cos(t))dS\\=\int\limits^\pi _0{3*(1+cos(t))dt

we solve the integral:

m=3*\int\limits^\pi _0{(1+cos(t))dt= 3*(t+sin(t))\limits^\pi _0=3*\pi=9.42

7 0
3 years ago
1000-kg car travelling down on a steepest road, which has inclined angle of 18
eduard

Answer:

1

Explanation:

it was thinking about how much and then the other than you can get it would be able to ask her to be able and then the way you have been sent from your browser

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