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Furkat [3]
3 years ago
6

Jocko the clown, whose mass is 60-Kg, stands on a skateboard. A 20-Kg ball is thrown at Jocko at 3m/s, and when he catches the b

all, he and the ball move on the skateboard. How fast do Jocko and the ball move after he catches the ball?
Physics
1 answer:
Mekhanik [1.2K]3 years ago
7 0

Answer:

The speed of the Jocko and the ball move after he catches the ball is 0.75 m/s.

Explanation:

Given that,

Mass if Jocko, m = 60 kg

Mass of the ball, m' = 20 kg

Speed of the ball, v = 3 m/s

Let V is the speed of Jocko and the ball move after he catches the ball. The momentum of the system remains conserved. Using the conservation of momentum as :

m'v'=(m+m')V\\\\V=\dfrac{m'v'}{(m+m')}\\\\V=\dfrac{20\times 3}{(60+20)}\\\\V=0.75\ m/s

So, the speed of the Jocko and the ball move after he catches the ball is 0.75 m/s.

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Solve the following problem showing all work, the formula, and correct units.
Temka [501]

5g/cm³

it is not iron.

Explanation:

Given parameters:

Density of iron = 7.874g/cm³

Mass of metal = 2000g

Volume of metal = 400cm³

Unknown:

Density of bar = ?

Is it iron = ?

Solution:

The density of a substance is its mass per unit area. Every substance have an intensive density value that typifies them all.

The density of water and other substances are the same if they maintain their level of pureness.

   Density = \frac{mass }{volume}

Density of metal bar = \frac{2000}{400} = 5g/cm³

Since this value is not the same as the given density of iron, it is not iron.

learn more:

Density brainly.com/question/5055270

learnwithBrainly

8 0
3 years ago
A frog jumps vertically upward from a 20m tall building with an initial velocity of 8.1m/s. How high above the ground will the f
topjm [15]

Answer:

Explanation:

Consider the initial position of the frog (20 m above ground) as the reference position. All measurements are positive measured upward.

Therefore,

u = 10 m/s, initial upward velocity.

H = - 20 m, position of the ground.

g = 9.8 m/s², acceleration due to gravity.

Part (a)

When the frog reaches a maximum height of h from the reference position, its velocity is zero. Therefore

u² - 2gh = 0

h = u²/(2g) = 10²/(2*9.8) = 5.102 m

At maximum height, the frog will be 20 + 5.102 = 25.102 m above ground.

Answer: 25.1 m above ground

Part (b)

Let v = the velocity when the frog hits the ground. Then

v² = u² - 2gH

v² = 10² - 2*9.8*(-20) = 492

v = 22.18 m/s

Answer: The frog hits the ground with a velocity of 22.2 m/s

8 0
4 years ago
When two objects made of different materials are rubbed together, they will attract each other after the charging process.Immers
Sergio039 [100]

Answer:

True

Explanation:

because their is friction(e.g take a ruler rub it in your hair then put it on top of a piece of paper on the table then u will see the process)among the two objects.

4 0
2 years ago
Rex makes himself a bowl of cereal. He puts 28 g of cereal in a bowl and then adds 245 g of milk. Before eating the cereal, he r
Galina-37 [17]

Answer:

A.)

Explanation:

Because you didn't add anything or take anything away.

5 0
3 years ago
a plane being propelled due east is actually moving at 225mph an angle of 40 degrees north of east, how fast is the crosswind th
Marianna [84]

Answer:

144.63 mph

Explanation:

225 sin (40)

4 0
3 years ago
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