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svp [43]
3 years ago
15

Jane and John Doppler effect

Physics
1 answer:
UkoKoshka [18]3 years ago
4 0

Answer:

To summarize, <em><u>Jane's star</u></em> has a <em><u>red</u></em> light and <em><u>is traveling towards</u></em> the <em><u>Earth</u></em> while <em><u>John's star </u></em>has a <em><u>blue</u></em> light and <em><u>is traveling away</u></em> from the <em><u>Earth</u></em>. This is a <em><u>prime example</u></em> of the <em><u>Doppler Effect</u></em> in <em><u>motion</u></em>. The stars <em><u>look different </u></em>because <em><u>they are traveling in different directions.</u></em>

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Even when shut down after a period of normal use, a large commercial nuclear reactor transfers thermal energy at the rate of 150
Phoenix [80]

Answer:

The temperature of the core raises by 2.8^{o}C every second.

Explanation:

Since the average specific heat of the reactor core is 0.3349 kJ/kgC

It means that we require 0.3349 kJ of heat to raise the temperature of 1 kg of core material by 1 degree Celsius

Thus reactor core whose mass is 1.60\times 10^{5}kg will require

0.3349\times 1.60\times 10^{5}kJ\\\\=0.53584\times 10^{5}kJ

energy to raise it's temperature by 1 degree Celsius in 1 second

Hence by the concept of proportionately we can infer 150 MW of power will increase the temperature by

\frac{150\times 10^{6}}{0.53584\times 10^{8}}=2.8^{o}C/s

5 0
3 years ago
What will a spring scale read for the weight of a 57.0-kg woman in an elevator that moves upward with constant speed of 5.0 m/s
Tanzania [10]
The spring scale will read 559 Newton's or 125.7 pounds.
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3 years ago
A steel drill making 180 rpm is used to drill a hole in a block of steel. The mass of the steel block and the drill is 180 g. If
SVETLANKA909090 [29]

Answer:

a) 37.8 W

b) 2 Nm

Explanation:

180 g = 0.18 kg

We can also convert 180 revolution per minute to standard angular velocity unit knowing that each revolution is 2π and 1 minute equals to 60 seconds

180 rpm = 180*2π/60 = 18.85 rad/s

We can use the heat specific equation to find the rate of heat exchange of the steel drill and block:

\dot{E} = mc\Delta \dot{t} = 0.18*420*0.5 = 37.8 J/s

Since the entire mechanical work is used up in producing heat, we can conclude that the rate of work is also 37.8 J/s, or 37.8 W

The torque T required to drill can be calculated using the work equation

E = T\theta

\dot{E} = T\dot{\theta} = T\omega

T = \frac{\dot{E}}{\omega} = \frac{37.8}{18.85} = 2 Nm

7 0
3 years ago
All objects emit ______ radiation?<br> A-electromagnetic<br> B-kinetic<br> D-solar
natulia [17]
A, electromagnetic radiation
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3 years ago
7. An 8 kg ball is travelling to the east at 10 ms', collides with a 2 kg ball travelling to the
Ymorist [56]

Answer:

The final velocity of the ball is 7m/s

Explanation:

M1=8kg,  V1 =10m/s , M2=2kg , V2=-5m/s

initial momentum before collison

m1v1+m2v2

=8×10 +2×(-5)  =80-10  = 70kg m/s

final momentum after collison

=(m1+m2)×v

=(8+2)×v

=10v

According to the law of conversion of momentum

initial momentum =final momentum

70=10v

10v=70

v=70/10

v=7m/s

3 0
3 years ago
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