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viva [34]
3 years ago
10

Suppose that an electromagnetic wave which is linearly polarized along the x−axis is propagating in vacuum along the z−axis. The

wave is incident on a conductor which is placed at z > 0 region of the space. The conductor has conductivity σ, magnetic permeability µ and electric permittivity ε.
(a) Find the characteristic time for the free charge density which dissipates at the conductor.

(b) Write the Maxwell equations and derive the wave equation for a plane wave propagating in a conductor.

(c) Find the attenuation distance at which the incident amplitude reduces to e ^−1 of its initial value.

(d) Find the electric and magnetic fields inside the conductor. 8 (e) Find the power loss per area of the incident electromagnetic wave at the surface of conductor.
Physics
1 answer:
goldfiish [28.3K]3 years ago
7 0
I think the answer to your question is B
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A hockey puck initially travelling to the right at 34 m/s. It moves for 7 before
goldfiish [28.3K]

Answer:

x=119m

Explanation:

Hello,

In this case, since the hockey puck was moving at 34 m/s and suddenly stopped (final velocity is zero) in 7 seconds, we can first compute the acceleration via:

a=\frac{v_f-v_o}{t}=\frac{0m/s-34m/s}{7s}\\  \\a=-4.86m/s^2

In such a way, we can compute the displacement via:

x=\frac{v_f^2-v_o^2}{2a}\\ \\x=\frac{0^2-(34m/s)^2}{2*-4.86m/s^2}\\ \\x=119m

Best regards.

3 0
3 years ago
HELP ASAP
andrezito [222]
It has both kinetic and potential
3 0
4 years ago
Read 2 more answers
Cho mạch như hình vẽ E
labwork [276]

Answer:

A

Explanation:

8 0
3 years ago
A simple pendulum is used to determine the acceleration due to gravity at the surface of a planet. The pendulum has a length of
SVEN [57.7K]

Answer:

Acceleration due to gravity is 20 m/sec^2

So option (E) will be correct answer

Explanation:

We have given length of the pendulum l = 2 m

Time period of the pendulum T = 2 sec

We have to find acceleration due to gravity g

We know that time period of pendulum is given by

T=2\pi \sqrt{\frac{l}{g}}

2=2\times 3.14 \sqrt{\frac{2}{g}}

0.3184= \sqrt{\frac{2}{g}}

Squaring both side

0.1014= {\frac{2}{g}}

g=19.71=20m/sec^2

So acceleration due to gravity is 20 m/sec^2

So option (E) will be correct answer.

8 0
3 years ago
Question 3 of 10
Eva8 [605]

Answer:

D. Newton's second law

Explanation:

Newton's second law of motion states that force of an object is a product of its mass and its acceleration.

Mathematically, F= ma where  m is mass and a is acceleration

So from the statement above : The acceleration of an object is proportional to the force applied to it and  inversely proportional to its mass , it can be seen from the formula variation as;

F= ma -----making a the subject of the formula

a= F/ m

a= 1/m * F --------- a  is inversely related to m  as you can see from 1/m but directly related to F  hence;

Increase in mass with the same force applied causes the body to accelerate slower where as when force increases, the body accelerates faster.

5 0
3 years ago
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