The work done by the shopping basket is 147 J.
<h3>When is work said to be done?</h3>
Work is said to be done whenever a force moves an object through a certain distance.
The amount of work done on the shopping basket can be calculated using the formula below.
Formula:
Where:
- W = Amount of work done by the basket
- m = mass of the shopping basket
- h = height of the shopping basket
- g = acceleration due to gravity.
Form the question,
Given:
- m = 10 kg
- h = 1.5 m
- g = 9.8 m/s²
Substitute these values into equation 2
- W = 10(1.5)(9.8)
- W = 147 J.
Hence, The work done by the shopping basket is 147 J.
Learn more about work done here: brainly.com/question/18762601
They both weigh the same. Since they both weigh 2g :)
Answer:
3.26 secs
Explanation:
Diameter of sphere ( D )= 10 mm
T1 = 75°C
P = 1 atm
T∞ = 23°C
T2 = 35°c
Velocity = 10 m/s
<u>Determine how long it will take to cool the sphere to 35°C</u>
<em>Using the properties of copper and air given in the question</em>
Nu = 2 + (Re)^0.8 (Pr)^0.33
hd / k = 2 + ( vd/v )^0.8 (Pr)^0.33
∴ h ≈ 2594.7 W/m^2k
Given that :
(T2 - T∞) / ( T1 - T∞ ) = exp [ ( -hA / pv CP ) t ]
( 35 - 23 ) / ( 75 - 23 ) = exp [ - 2594.7 * 6 * t / 8933 * 387 * 10 * 10^-3 ]
= ln ( 12/52 ) = -1.466337069 = - 0.45032919 * t
∴ t ≈ 3.26 secs ( -1.466337069 / -0.45032919 )
If the student (which I’m naming student “x”) starts off at running 200m/30secs, then accelerated to 300m/30secs. If it was one minute later, I naturally assume she increases 100m/20secs.