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viva [34]
3 years ago
10

Suppose that an electromagnetic wave which is linearly polarized along the x−axis is propagating in vacuum along the z−axis. The

wave is incident on a conductor which is placed at z > 0 region of the space. The conductor has conductivity σ, magnetic permeability µ and electric permittivity ε.
(a) Find the characteristic time for the free charge density which dissipates at the conductor.

(b) Write the Maxwell equations and derive the wave equation for a plane wave propagating in a conductor.

(c) Find the attenuation distance at which the incident amplitude reduces to e ^−1 of its initial value.

(d) Find the electric and magnetic fields inside the conductor. 8 (e) Find the power loss per area of the incident electromagnetic wave at the surface of conductor.
Physics
1 answer:
goldfiish [28.3K]3 years ago
7 0
I think the answer to your question is B
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Vitek1552 [10]
The main formula is given by Eb/nucleon = Eb/ mass of nucleid
as for <span>52He, the mass is 5
so by applying Einstein's formula Eb=DmC², Eb=</span><span>binding energy
</span><span>52He-----------> 2 x 11p + 3 x10n is the equation bilan
</span>so Dm=2 mp + (5-2)mn-mnucleus, mp=mass of proton=1.67 10^-27 kg
                                                        mn=mass of neutron=<span>1.67 10^-27 kg
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Dm= 2x</span>1.67 10^-27 kg+ 3x<span>1.67 10^-27 kg-5=  - 4.9 J
Eb= </span> - <span>4.9 J x c²= -4.9 x 9 .10^16= - 45 10^16 J
so the answer is Eb /nucleon = Eb/5= -9.10^16 J, but 1eV=1.6 . 10^-19 J
so </span><span>-9.10^16 J/ 1.6 10^-19=  -5.625 10^35 eV

the final answer is </span><span>Eb /nucleon </span><span>=  -5.625 x10^35 eV</span>
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