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Masja [62]
3 years ago
7

Which way do electrons within a rectangular rod move when a negatively-charged balloon is brought near a positively-charged rod?

Physics
1 answer:
Gnom [1K]3 years ago
7 0

Answer: They would attract each other

Explanation:

Opposites attract

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The physics of wind instruments is based on the concept of standing waves. When the player blows into the mouthpiece, the column
Fed [463]

Answer:

1. 214.38hz

2. higher than before.

Explanation:

1. the lowest frequency f of the sound wave produced

f = v/2L

l = 80cm = 0.8m

v = 343 metre per second, this is the sound speed of air

f = 343/2*0.8

the lowest frequency = 214.38hz

2. Since there is ahle n the pipe, this would shorten the length of air column that is able to oscillate in this pipe. we use the same formula as we used in question 1 here.

Vf ∝1/L

so we conclude that, c. it is higher than before

7 0
2 years ago
Astrologists use the positions of the stars to make predictions about the future. Why is astrology a pseudoscience?
Sunny_sXe [5.5K]
Because it is a collection of beliefs mistakenly regarded as being based as specific method




please can i have a brainliest
7 0
3 years ago
Read 2 more answers
A child is trying to throw a ball over a fence. She gives the ball an initial speed of 8.0 m/s at an angle of 40° above the hori
EastWind [94]

Answer:

the child is 1.581 m far from the fence

Explanation:

The diagrammatic illustration that give a better view of what the question denote can be seen in the image attached below.

From the image attached below, let assume that the release point is the origin, then equation of the motion (x) is as follows:

x - x_o = u_xt

\mathtt{x = u_xt  \ \  \ since (x_o = 0)}  ---- (1)

the equation of the motion y is :

\mathtt{y - y_o =u_yt - 0.5 gt^2}

\mathtt{y = u_yt-4.9t^2     \ \ \  since (y_o =0)}

\mathtt{ 1= (u \ sin 40^0)t -4.9 \ t^2        }

\mathtt{1 = 8 sin 40^0 t - 4.9 t^2}

\mathtt{1 = 5.14t - 4.9t^2}

\mathtt{4.9t^2 - 5.14t +1 = 0}

By using the quadratic formula, we have;

\mathtt{ \dfrac{ -b \pm \sqrt{b^2 - 4ac}}{2a}}     }

where;

a = 4.9,   b = -5.14     c = 1

= \mathtt{ \dfrac{ -(-5.14) \pm \sqrt{(-5.14)^2 - 4(4.9)(1)}}{2(4.9)}}     }

= \mathtt{ \dfrac{ 5.14 \pm \sqrt{26.4196 -19.6}}{9.8}}     }

= \mathtt{ \dfrac{ 5.14 \pm \sqrt{6.8196}}{9.8}}     }

= \mathtt{ \dfrac{ 5.14+ \sqrt{6.8196}}{9.8}  \  \ OR \  \  \dfrac{ 5.14- \sqrt{6.8196}}{9.8}}    }

= \mathtt{ \dfrac{ 5.14+ 2.6114}{9.8}  \  \ OR \  \  \dfrac{ 5.14- 2.6114}{9.8}}    }

= \mathtt{ \dfrac{ 7.7514}{9.8}  \  \ OR \  \  \dfrac{ 2.5286}{9.8}}    }

= \mathbf{ 0.791 \  \ OR \  \  0.258}    }

In as much as the ball is traveling upward, then we consider t= 0.258sec.

From equation (1)

\mathtt{x = u_x(0.258)}

\mathtt{x = ucos 40^0 (0.258)}

\mathtt{x = 8 \ cos 40^0 (0.258)}

\mathbf{x = 1.581  \ m}

Thus, the child is 1.581 m far from the fence

6 0
3 years ago
HELP!!
Diano4ka-milaya [45]
The question in choice-C is the correct answer to your question.

(Is this confusing ?)
6 0
3 years ago
Read 2 more answers
Which is an example of a scientist using a conceptual model to describe a volcano?
Yuri [45]
I would say D would be the answer. but is this even a real like homework question 

8 0
3 years ago
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