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Semmy [17]
3 years ago
10

John read the first 114114114 pages of a novel, which was 333 pages less than \dfrac13 3 1 ​ start fraction, 1, divided by, 3, e

nd fraction of the novel. Write an equation to determine the total number of pages (p)(p)left parenthesis, p, right parenthesis in the novel. John read the first 114114114 pages of a novel, which was 333 pages less than \dfrac13 3 1 ​ start fraction, 1, divided by, 3, end fraction of the novel. Write an equation to determine the total number of pages (p)(p)left parenthesis, p, right parenthesis in the novel. John read the first 114114114 pages of a novel, which was 333 pages less than \dfrac13 3 1 ​ start fraction, 1, divided by, 3, end fraction of the novel. Write an equation to determine the total number of pages (p)(p)left parenthesis, p, right parenthesis in the novel. John read the first 114114114 pages of a novel, which was 333 pages less than \dfrac13 3 1 ​ start fraction, 1, divided by, 3, end fraction of the novel. Write an equation to determine the total number of pages (p)(p)left parenthesis, p, right parenthesis in the novel. John read the first 114114114 pages of a novel, which was 333 pages less than \dfrac13 3 1 ​ start fraction, 1, divided by, 3, end fraction of the novel. Write an equation to determine the total number of pages (p)(p)left parenthesis, p, right parenthesis in the novel. John read the first 114114114 pages of a novel, which was 333 pages less than \dfrac13 3 1 ​ start fraction, 1, divided by, 3, end fraction of the novel. Write an equation to determine the total number of pages (p)(p)left parenthesis, p, right parenthesis in the novel. John read the first 114114114 pages of a novel, which was 333 pages less than \dfrac13 3 1 ​ start fraction, 1, divided by, 3, end fraction of the novel. Write an equation to determine the total number of pages (p)(p)left parenthesis, p, right parenthesis in the novel. John read the first 114114114 pages of a novel, which was 333 pages less than \dfrac13 3 1 ​ start fraction, 1, divided by, 3, end fraction of the novel. Write an equation to determine the total number of pages (p)(p)left parenthesis, p, right parenthesis in the novel. John read the first 114114114 pages of a novel, which was 333 pages less than \dfrac13 3 1 ​ start fraction, 1, divided by, 3, end fraction of the novel. Write an equation to determine the total number of pages (p)(p)left parenthesis, p, right parenthesis in the novel. John read the first 114114114 pages of a novel, which was 333 pages less than \dfrac13 3 1 ​ start fraction, 1, divided by, 3, end fraction of the novel. Write an equation to determine the total number of pages (p)(p)left parenthesis, p, right parenthesis in the novel. John read the first 114114114 pages of a novel, which was 333 pages less than \dfrac13 3 1 ​ start fraction, 1, divided by, 3, end fraction of the novel. Write an equation to determine the total number of pages (p)(p)left parenthesis, p, right parenthesis in the novel. John read the first 114114114 pages of a novel, which was 333 pages less than \dfrac13 3 1 ​ start fraction, 1, divided by, 3, end fraction of the novel. Write an equation to determine the total number of pages (p)(p)left parenthesis, p, right parenthesis in the novel. John read the first 114114114 pages of a novel, which was 333 pages less than \dfrac13 3 1 ​ start fraction, 1, divided by, 3, end fraction of the novel. Write an equation to determine the total number of pages (p)(p)left parenthesis, p, right parenthesis in the novel. John read the first 114114114 pages of a novel, which was 333 pages less than \dfrac13 3 1 ​ start fraction, 1, divided by, 3, end fraction of the novel. Write an equation to determine the total number of pages (p)(p)left parenthesis, p, right parenthesis in the novel. John read the first 114114114 pages of a novel, which was 333 pages less than \dfrac13 3 1 ​ start fraction, 1, divided by, 3, end fraction of the novel. Write an equation to determine the total number of pages (p)(p)left parenthesis, p, right parenthesis in the novel. John read the first 114114114 pages of a novel, which was 333 pages less than \dfrac13 3 1 ​ start fraction, 1, divided by, 3, end fraction of the novel. Write an equation to determine the total number of pages (p)(p)left parenthesis, p, right parenthesis in the novel. John read the first 114114114 pages of a novel, which was 333 pages less than \dfrac13 3 1 ​
Engineering
1 answer:
sineoko [7]3 years ago
8 0

Question:

John read the first 114 pages of a novel, which was 3 pages less than ⅓ of the novel. Write an equation to determine the total number of pages (P)

Answer:

114 = ⅓P - 3

Explanation:

Given

Number of pages read = 114

Total pages in novel = p

The relationship between the pages read by John and the total pages is analysed as follows:

3 less than ⅓ of total pages means:

⅓ of total pages - 3

Recall that P represents the total pages in the novel

So, the expression becomes

⅓ * P - 3

⅓P - 3

This means that the pages read by John is ⅓P - 3

This implies that the equation to determine the number of pages in the novel is

⅓P - 3 = 114

Solving further to get the actual number of pages;

Multiply both sides by 3

3(⅓P - 3) = 114 * 3

3 * ⅓P - 3 * 3 = 114 * 3

P - 9 = 342

Add 9 to both sides

P - 9 + 9 = 342 + 9

P = 351

Hence the number of pages is 351

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The fracture strength of glass may be increased by etching away a thin surface layer. It is believed that the etching may alter
Korvikt [17]

Answer:

the ratio of the etched to the original crack tip radius is 30.24

Explanation:

Given the data in the question;

we determine the initial fracture stress using the following expression;

(σf)₁ = 2(σ₀)₁ [ α₁/(p_t)₁ ]^{1/2 ----- let this be equation 1

where; (σ₀)₁ is the initial fracture strength

(p_t)₁ is the original crack tip radius

α₁ is the original crack length.

first, we determine the final crack length;

α₂ = α₁ - 16% of α₁

α₂ = α₁ - ( 0.16 × α₁)

α₂ = α₁ - 0.16α₁

α₂ = 0.84α₁

next, we calculate the final fracture stress;

the fracture strength is increased by a factor of 6;

(σ₀)₂ = 6( σ₀ )₁

Now, expression for the final fracture stress

(σf)₂ = 2(σ₀)₂ [ α₂/(p_t)₂ ]^{1/2 ------- let this be equation 2

where (p_t)₂ is the etched crack tip radius

value of fracture stress of glass is constant

Now, we substitute 2(σ₀)₁ [ α₁/(p_t)₁ ]^{1/2 from equation for (σf)₂  in equation 2.

0.84α₁ for α₂.

6( σ₀ )₁ for (σ₀)₂.

∴

2(σ₀)₁ [ α₁/(p_t)₁ ]^{1/2  = 2(6( σ₀ )₁) [ 0.84α₁/(p_t)₂ ]^{1/2  

divide both sides by 2(σ₀)₁

[ α₁/(p_t)₁ ]^{1/2  =  6 [ 0.84α₁/(p_t)₂ ]^{1/2

[ 1/(p_t)₁ ]^{1/2  =  6 [ 0.84/(p_t)₂ ]^{1/2

[ 1/(p_t)₁ ]  =  36 [ 0.84/(p_t)₂ ]

1 / (p_t)₁ = 30.24 / (p_t)₂

(p_t)₂ = 30.24(p_t)₁

(p_t)₂/(p_t)₁ = 30.24

Therefore, the ratio of the etched to the original crack tip radius is 30.24

6 0
3 years ago
weight of 1000 pounds is suspended from two cables. The allowable stress in the cables is 1500 psi. Find the minimum diameter fo
kari74 [83]

Answer:

The minimum diameter for each cable should be 0.65 inches.

Explanation:

Since, the load is supported by two ropes and the allowable stress in each rope is 1500 psi. Therefore,

(1/2)(Weight/Cross Sectional Area) = Allowable Stress

Here,

Weight = 1000 lb

Cross-sectional area = πr²

where, r = minimum radius for each cable

(1/2)(1000 lb/πr²) = 1500 psi

500 lb/1500π psi = r²

r = √1.061 in²

r = 0.325 in

Now, for diameter:

Diameter = 2(radius) = 2r

Diameter = 2(0.325 in)

<u>Diameter = 0.65 in</u>

7 0
2 years ago
HAPPINESS DISCUSSION
RideAnS [48]

Answer:

uh because life sucks o_<

8 0
2 years ago
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Select the correct answer. which process involves creating a product by heating metals and changing their shape through the appl
Paraphin [41]

Answer:

I would say that it is forming.

Explanation:

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4 0
2 years ago
Steam enters a turbine operating at steady state with a mass flow of 10 kg/min, a specific enthalpy of 3100 kJ/kg, and a velocit
Natali [406]

Answer:

\dot W_{out} = 133.327\,kW

Explanation:

The model for the turbine can be derived by means of the First Law of Thermodynamics:

-\dot Q_{out}-\dot W_{out} +\dot m \cdot \left[(h_{in}-h_{out})+\frac{1}{2}\cdot (v_{in}^{2}-v_{out}^{2}) + g\cdot (z_{in}-z_{out})\right] =0

The work produced by the turbine is:

\dot W_{out}=-\dot Q_{out} +\dot m \cdot \left[(h_{in}-h_{out})+\frac{1}{2}\cdot (v_{in}^{2}-v_{out}^{2}) + g\cdot (z_{in}-z_{out})\right]

The mass flow and heat transfer rates are, respectively:

\dot m = (10\frac{kg}{min})\cdot (\frac{1\,min}{60\,s} )

\dot m = 0.167\,\frac{kg}{s}

\dot Q_{out} = (0.167\,\frac{kg}{s} )\cdot (1.1\times 10^{3}\,\frac{J}{kg} )

\dot Q_{out} = 183.7\,W

Finally:

\dot W_{out} = -183.7\,W + (0.167\,\frac{kg}{s} )\cdot \left(8\times 10^{5}\,\frac{J}{kg} -562,5\,\frac{J}{kg} +29.43\,\frac{J}{kg} \right)

\dot W_{out} = 133.327\,kW

3 0
3 years ago
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