How do you build a house.
1 answer:
You might be interested in
Complete Question
For some metal alloy, a true stress of 345 MPa (50040 psi) produces a plastic true strain of 0.02. How much will a specimen of this material elongate when a true stress of 411 MPa (59610 psi) is applied if the original length is 470 mm (18.50 in.)?Assume a value of 0.22 for the strain-hardening exponent, n.
Answer:
The elongation is
Explanation:
In order to gain a good understanding of this solution let define some terms
True Stress
A true stress can be defined as the quotient obtained when instantaneous applied load is divided by instantaneous cross-sectional area of a material it can be denoted as .
True Strain
A true strain can be defined as the value obtained when the natural logarithm quotient of instantaneous gauge length divided by original gauge length of a material is being bend out of shape by a uni-axial force. it can be denoted as .
The mathematical relation between stress to strain on the plastic region of deformation is
Where K is a constant
n is known as the strain hardening exponent
This constant K can be obtained as follows
No substituting from the question we have
Making the subject from the equation above
From the definition we mentioned instantaneous length and this can be obtained mathematically as follows
Where
is the instantaneous length
is the original length
We can also obtain the elongated length mathematically as follows
Answer:
t = 25.10 sec
Explanation:
we know that Avrami equation
here Y is percentage of completion of reaction = 50%
t is duration of reaction = 146 sec
so,
taking natural log on both side
ln(0.5) = -k(306.6)
for 86 % completion
t = 25.10 sec
Answer:
I am writing a Python program. Here is the function letterCount. This function takes two string arguments text and letter and return count of all occurrences of a letter in the text.
def letterCount(text, letter):
count = 0 # to count occurrences of letter in the text string
for char in text: # loop moves through each character in the text
if letter == char: # if given letter matches with the value in char
count += 1 # keeps counting occurrence of a letter in text
return count # returns how many times a letter occurred in text
Explanation:
In order to see if this function works you can check by calling this function and passing a text and a letter as following:
print(letterCount('apples are tasty','a'))
Output:
3
Now lets see how this function works using the above text and letter values.
text = apples are tasty
letter = a
So the function has to compute the occurrences of 'a' in the given text 'apples are tasty'.
The loop has a variable char that moves through each character given in the text (from a of apples to y of tasty) so it is used as an index variable.
char checks each character of the text string for the occurrence of letter a.
The if condition checks if the char is positioned at a character which matches the given letter i.e. a. If it is true e.g if char is at character a of apple so the if condition evaluates to true.
When the if condition evaluates to true this means one occurrence is found and this count variable counts this occurrence. So count increments every time the occurrence of letter a is found in apples are tasty text.
The loop breaks when every character in text is traversed and finally the count variable returns all of the occurrences of that letter (a) in the given text (apples are tasty). As a occurs 3 times in text so 3 is returned in output.
The screen shot of program along with output is attached.
