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sesenic [268]
2 years ago
9

9. Triacylglycerols are

Chemistry
1 answer:
Ket [755]2 years ago
4 0

Answer:

b. insoluble in water

Explanation:

triacylglycerols are insoluble in water

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How many moles of sulfur trioxide are formed from 3 moles of oxygen using the given
fiasKO [112]

Answer:

6 moles of SO₃ formed.

Explanation:

Given data:

Number of moles of SO₃ formed = ?

Number of moles of oxygen react = 3 mol

Solution:

Chemical equation;

2SO₂+ O₂      →   2SO₃

now we will compare the moles of oxygen and sulfur trioxide.

                             O₂            :            SO₃

                               1             :             2

                               3            :           2/1×3 = 6 moles

Thus, six moles of SO₃ will formed.

8 0
2 years ago
A hydrogen filled balloon has a volume of 8.3 L at 36°C and 751 mmHg. How many moles of hydrogen are inside the balloon?
tamaranim1 [39]

Answer: I think the formula is PV=nRT and I divide both sides by RT, but this is as far as I can get in my equation before I get stumped: (751 mm Hg) (8.3 L)/ (309 K) Can you help?

Explanation:

8 0
2 years ago
Which two scientists discovered the subatomic particles that make up the nucleus
bazaltina [42]
Neutrons were discovered by James Chadwick<span> in 1932, when he demonstrated that penetrating radiation incorporated beams of neutral particles. Neutrons are located in the nucleus with the protons. Along with protons, they make up almost all of the mass of the </span>atom<span>.

Hope this helps. </span>
6 0
2 years ago
CH4 with pressure 1 atm and volume 10 liter at 27°C is passed into a reactor with 20% excess oxygen, how many moles of oxygen is
BaLLatris [955]

Answer : The moles of O_2 left in the products are 0.16 moles.

Explanation :

First we have to calculate the moles of CH_4.

Using ideal gas equation:

PV=nRT

where,

P = pressure of gas = 1 atm

V = volume of gas = 10 L

T = temperature of gas = 27^oC=273+27=300K

n = number of moles of gas = ?

R = gas constant = 0.0821 L.atm/mol.K

Now put all the given values in the ideal gas equation, we get:

(1atm)\times (10L)=n\times (0.0821L.atm/mol.K)\times (300K)

n=0.406mole

Now we have to calculate the moles of O_2.

The balanced chemical reaction will be:

CH_4+2O_2\rightarrow CO_2+2H_2O

From the balanced reaction we conclude that,

As, 1 mole of CH_4 react with 2 moles of O_2

So, 0.406 mole of CH_4 react with 2\times 0.406=0.812 moles of O_2

Now we have to calculate the excess moles of O_2.

O_2 is 20 % excess. That means,

Excess moles of O_2 = \frac{(100 + 20)}{100} × Required moles of O_2

Excess moles of O_2 = 1.2 × Required moles of O_2

Excess moles of O_2 = 1.2 × 0.812 = 0.97 mole

Now we have to calculate the moles of O_2 left in the products.

Moles of O_2 left in the products = Excess moles of O_2 - Required moles of O_2

Moles of O_2 left in the products = 0.97 - 0.812 = 0.16 mole

Therefore, the moles of O_2 left in the products are 0.16 moles.

7 0
3 years ago
What mass of oxygen is contained in a 5.8 g sample of NaHCO3?
jarptica [38.1K]
X:5.8g=16:(23+1+12+3*16)
x:5.=16:84 
x:=5.8* 16/84 
this is approximately 1.1
4 0
2 years ago
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