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3 years ago

A graphical representation of the strength of an acid or base.

Physics

1 answer:

guapka [62]3 years ago

7 0

Answer:

pH Scale

Explanation:

I attached a picture of the pH scale too if you needed that as well.

Hope this helped! :)

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An object starts from rest and accelerates at a rate of 3.0 m/s/s for 6.0 seconds. The velocity at the end of the 6.0 seconds is

Zepler [3.9K]

Vf=vi+at
=0+3×6
=18m/s

the answer is D.

6 0

3 years ago

A noninverting op-amp circuit with a gain of 96 V/V is found to have a 3-dB frequency of 8 kHz. For a particular system applicat

umka21 [38]

Answer:

$Av_2 =24\ V/V$

Explanation:

given,

op-amp circuit with a gain of = (Av₁) = 96 V/V

Band width = (Bw₁) = 8 kHz

Required bandwidth(Bw₂) = 32 kHz

Highest gain available =(Av₂) = ?

For the given system Bandwidth product is constant

Av₁ Bw₁ = Av₂ Bw₂

96 x 8 = Av₂ x 32

$Av_2= \dfrac{96\times 8}{32}$

$Av_2 =24\ V/V$

the highest gain available under these conditions $Av_2 =24\ V/V$

6 0

3 years ago

What results from splitting an atomic nucleus

Burka [1]

A uranium-235 atom absorbs a neutron and fissions into two new atoms (fission fragments), releasing three new neutrons and some binding energy. ... Several heavy elements, such as uranium, thorium, and plutonium, undergo both spontaneous fission, a form of radioactive decay and induced fission, a form of nuclear reaction.

7 0

3 years ago

Read 2 more answers

Express 4,560 m in Km

Gala2k [10]

4.56 km is the answer

7 0

3 years ago

Read 2 more answers

two electrons are an angstrom (1x10^-10m) apart. What electrostatic force do they exert on one another?

Irina-Kira [14]

Answer:

2.30 × 10⁻⁸ N if the two electrons are in a vacuum.

Explanation:

The Coulomb's Law gives the size of the electrostatic force $F$ between two charged objects:

$\displaystyle F = -\frac{k\cdot q_1 \cdot q_2}{r^{2}}$ ,

where

$k$ is coulomb's constant. $k = 8.99\times 10^{8}\;\text{N}\cdot\text{m}^{2}\cdot\text{C}^{-2}$ in vacuum.
$q_1$ and $q_2$ are the signed charge of the objects.
$r$ is the distance between the two objects.

For the two electrons:

$q_1 = q_2 = 1.60\times 10^{-19}\;\text{C}$ .
$r = 1\times 10^{-10}\;\text{m}$ .

$\displaystyle F = -\frac{k\cdot q_1 \cdot q_2}{r^{2}} = -\frac{8.99\times 10^{8}\times (1.60\times 10^{-19})^{2}}{(1\times 10^{-10})^{2}} = 2.30\times 10^{-8}\;\text{N}$ .

The sign of $F$ is negative. In other words, the two electrons repel each other since the signs of their charges are the same.

8 0

3 years ago