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Slav-nsk [51]
3 years ago
15

A box is given a push so that it slides across the floor. how far will it go given that the How far will it go, given that the c

oefficient of kinetic friction is 0.13 and the push imparts an initial speed of 3.5 m/s
Physics
1 answer:
melisa1 [442]3 years ago
6 0

Answer:

4.808m

Explanation:

Force is given as:

F = ma

Since the force is a frictional force,

Fr = F

Fr = ma

Frictional force, Fr, is given as:

-umg = ma

a = -ug = -0.13 * 9.8 = -1.274 m/s²

Using one of the equations of motion, we can find the distance:

v² = u² + 2as

Since the box comes to a halt, v = 0m/s:

0 = u² + 2as

s = -u²/2a

s = -(-3.5²)/(2 * 1.274) = 4.808m

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Coherent light of wavelength 525 nm passes through two thin slits that are 4.15×10^(−2) mm apart and then falls on a screen 7
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A) 4.7 cm

The formula for the angular spread of the nth-maximum from the central bright fringe for a diffraction from two slits is

sin \theta=\frac{n \lambda}{d}

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a is the distance between the slits

In this problem,

n = 5

\lambda=525 nm =5.25\cdot 10^{-7} m

a=4.15\cdot 10^{-2} mm=4.15\cdot 10^{-5} m

So we find

\theta=sin^{-1} (\frac{(5)(5.25\cdot 10^{-7} m)}{4.15\cdot 10^{-5} m})=3.62^{\circ}

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The distance of the 5th  bright fringe from the central bright fringe will be given by

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B) 8.1 cm

The formula to find the nth-minimum (dark fringe) in a diffraction pattern from double slit is a bit differente from the previous one:

sin \theta=\frac{(n+\frac{1}{2}) \lambda}{d}

To find the angle corresponding to the 8th dark fringe, we substitute n=8:

\theta=sin^{-1} (\frac{(8+\frac{1}{2})(5.25\cdot 10^{-7} m)}{4.15\cdot 10^{-5} m})=6.17^{\circ}

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5 0
3 years ago
Susan, driving north at 53 mphmph , and Shawn, driving east at 63 mphmph , are approaching an intersection. Part A What is Shawn
mafiozo [28]

Answer:

Shawn's speed relative to Susan's speed = 10 mph

Resultant velocity = 82.32 mph

Explanation:

The given data :-

i) Susan driving in north and speed of Susan is ( v₁ ) = 53 mph.

ii) Shawn driving in east and speed of Shawn is ( v₂ ) = 63 mph.

iii) The speed of both Susan and Shawn is relative to earth.

iv) The angle between Susan in north and Shawn in east is 90°.

We have to find Shawn's speed relative to Susan's speed.

v₂₁ = v₂ - v₁   = 63 - 53 = 10 mph

Resultant velocity,

v = \sqrt{v_{2} ^{2}+ v_{1} ^{2}  }  =\sqrt{63^{2} +53^{2} }

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3 years ago
What’s the four missing blanks in this diagram?
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Answer:

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Zak, helping his mother rearrange the furniture in their living room, moves a 60 kg sofa 5.9 m with a constant force of 40 N. Wh
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Answer:236 J

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W=40\cdot 5.9

W=236 J

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3 years ago
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