A noninverting op-amp circuit with a gain of 96 V/V is found to have a 3-dB frequency of 8 kHz. For a particular system applicat ion, a bandwidth of 32 kHz is required. What is the highest gain available under these conditions?
1 answer:
Answer:
Explanation:
given,
op-amp circuit with a gain of = (Av₁) = 96 V/V
Band width = (Bw₁) = 8 kHz
Required bandwidth(Bw₂) = 32 kHz
Highest gain available =(Av₂) = ?
For the given system Bandwidth product is constant
Av₁ Bw₁ = Av₂ Bw₂
96 x 8 = Av₂ x 32
the highest gain available under these conditions
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