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ipn [44]
3 years ago
9

A noninverting op-amp circuit with a gain of 96 V/V is found to have a 3-dB frequency of 8 kHz. For a particular system applicat

ion, a bandwidth of 32 kHz is required. What is the highest gain available under these conditions?
Physics
1 answer:
umka21 [38]3 years ago
6 0

Answer:

Av_2 =24\ V/V

Explanation:

given,

op-amp circuit with a gain of = (Av₁) = 96 V/V

Band width  = (Bw₁) = 8 kHz

Required bandwidth(Bw₂) = 32 kHz

Highest gain available =(Av₂) = ?

For the given system Bandwidth product is constant

                           Av₁ Bw₁ = Av₂ Bw₂

                           96 x 8 = Av₂ x 32

                           Av_2= \dfrac{96\times 8}{32}

                           Av_2 =24\ V/V

the highest gain available under these conditions Av_2 =24\ V/V

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horrorfan [7]

Answer:

1. all of them

2. cork and wax

3. iron, lead, and aluminum

4. none of them

Explanation:

1.Which material will displace a volume of water?  all of them

When an object is introduced into a container with a volume of water, a volume of liquid equal to the volume of the object is displaced

2.Which material will displace a volume of water less than its own volume?

cork and wax

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3.Which material will displace a volume of water equal to its own volume?

iron, lead, and aluminum

because  Arquimedes's principle: any body plunged inside a fluid in this case water experiences an ascending force called push, equivalent to the weight of the fluid removed by the body

4.Which material will displace a volume of water greater than its own volume?

None of them

7 0
3 years ago
The battery charger for an mp3 player contains a step-down transformer with a turns ratio of 1:24, so that the voltage of 120 v
miskamm [114]
Considering that we are talking about a stepdown transformer, and a turn ration of 1:24

Then

Vsecondary coil = 120 V / 24 = 5V

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8 0
4 years ago
Assuming that the uncertainty in mass is negligible, and the uncertainty in velocity is 5 %, what is the uncertainty in the mome
Flura [38]

Answer:

 Δp = 0.05 p

Explanation:

The moment is

      p = m v

The uncertainty of the moment is

       Δp = dp/dm Δm + dp/dv Δv

Like the uncertainty in the mass is zero

       Δm = 0

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We divide for the moment

       Δp / p = Δv / v

  They do not indicate that Δv / v = 0.05

       Δp / p = 0.05

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In the case of a system consisting of two cars

      p = m₁ v₁ + m₂ v₂

     Δp = dp / dv₁ Δv₁ + dp / dv₂ Δv₂

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     Δv₁ = 0.05 v₁

     Δv₂ / v₂ = 0.05

     Δv₂ = 0.05 v₂

We replace

       Δp = m₁ 0.05 v₁ + m₂ 0.05 v₂

       Δp = 0.05 p

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Answer:

The answer is True

Explanation:

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