Answer:
B. The mass of Mars is less than the mass of Earth.
Explanation:
Mass of an object is the constant anywhere in the universe.
The weight of an object is equal to the gravitational force acting on it.
Weight is given by
where
G = Gravitational constant
M = Mass of Planet
R = Radius of planet
m = Mass of object
g = Acceleration due to gravity
So weight of an object depends on the acceleration due to gravity on that planet. The acceleration due to gravity depends on the mass and radius of the planet.
The weight of the object is less on Mars because mars has less mass compared to Earth.
We need to directly measure the spectral type in order to determine the surface temperature of a star.
<h3>How do you find the properties of a star?</h3>
Astronomers can determine the temperature of a star by looking at its color and spectrum. The apparent brightness of a star describes how luminous it looks to us. The brightness of a star tells us how bright it really is. The luminance can be determined using both the perceived brightness and the distance.
A star's luminosity, or the total amount of energy it emits each second, is determined by two factors: The stellar photosphere's "Effective Temperature," T. the star's total surface area, which is influenced by its radius, R.
Because it controls how much fuel a star has and how quickly it burns it, a star's mass is its most fundamental characteristic. The majority of a star's life is spent burning hydrogen into helium in its core, which generates energy. The star needs to achieve a balance between gravity and outward pressure in order to continue to be "alive."
To know more about stellar property visit:
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It would have helped to answer this question, if there were some options to choose from. I am answering the question based on what i understood. I hope that it helps you. The teeth rip and grind food into small chunks. This is also the main function of the teeth and it does help in the digestion of the food we take.
Answer:
Approximately 
(assuming that the projectile was launched at angle of 
above the horizon.)
Explanation:
Initial vertical component of velocity:
.
The question assumed that there is no drag on this projectile. Additionally, the altitude of this projectile just before landing 
is the same as the altitude 
at which this projectile was launched: 
.
Hence, the initial vertical velocity of this projectile would be the exact opposite of the vertical velocity of this projectile right before landing. Since the initial vertical velocity is 
(upwards,) the vertical velocity right before landing would be 
(downwards.) The change in vertical velocity is:
.
Since there is no drag on this projectile, the vertical acceleration of this projectile would be 
. In other words, 
.
Hence, the time it takes to achieve a (vertical) velocity change of 
would be:
.
Hence, this projectile would be in the air for approximately .
Answer:
7. Your answer is correct dear, just add the unit
8. answer is 1.17m/s²
Explanation:
queation 7.
m = 3kg, F = 9N, a ?
F = ma
a = F/m = 9/3 = 3m/s²
Use the same approach for question 8
