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Elena-2011 [213]
1 year ago
7

- A straight wire, 0.20 m long, moves at a constant speed of 7.0 m/s

Physics
1 answer:
Elis [28]1 year ago
7 0

(a) The emf induced in the wire is 0.112 V.

(b) The direction of the current will into the page.

(c) The polarity of A will be positive and L will be negative.

(d)  The current flowing through the wire is 0.224 A.

<h3>EMF induced in the wire</h3>

The emf induced in the wire is calculated as follows;

EMF = BLv

EMF = (8 x 10⁻²) x 0.2 x 7

EMF = 0.112 V

<h3>Direction of the current</h3>

Since, the magnetic field is out of the page, the current will follow counter clockwise and will point into the page.

<h3>Polarity of point A and point L</h3>

The current is flowing counter currently, hence the polarity of A will be positive and L will be negative.

<h3>Current through the wire</h3>

V = IR

I = V/R

I = (0.112)/0.5

I = 0.224 A

Learn more about current here: brainly.com/question/24858512

#SPJ1

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A loop of wire is placed in a uniform magnetic field. For what orientation of the loop is the magnetic flux a maximum? For what
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3 years ago
Two satellites are in circular orbits around a planet that has radius 9.00x10^6 m. One satellite has mass 53.0 kg , orbital radi
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Answer:

The orbital speed of this second satellite is 5195.16 m/s.

Explanation:

Given that,

Orbital radius of first satellite r_{1}= 8.20\times10^{7}

Orbital radius of second satellite r_{2}=7.00\times10^{7}\ m

Mass of first satellite m_{1}=53.0\ kg

Mass of second satellite m_{2}=54.0\ kg

Orbital speed of first satellite = 4800 m/s

We need to calculate the orbital speed of this second satellite

Using formula of orbital speed

v=\sqrt{\dfrac{GM}{r}}

From this relation,

v_{1}\propto\dfrac{1}{\sqrt{r}}

Now, \dfrac{v_{1}}{v_{2}}=\sqrt{\dfrac{r_{2}}{r_{1}}}

v_{2}=v_{1}\times\sqrt{\dfrac{r_{1}}{r_{2}}}

Put the value into the formula

v_{2}=4800\times\sqrt{\dfrac{ 8.20\times10^{7}}{7.00\times10^{7}}}

v_{2}=5195.16\ m/s

Hence, The orbital speed of this second satellite is 5195.16 m/s.

4 0
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sp2606 [1]

Answer:

R2 = 300 Ohms

Explanation:

Let the two resistors be R1 and R2 respectively.

RT is the total equivalent resistance.

Given the following data;

R1 = 100 Ohms

RT = 75 Ohms

To find R2;

Mathematically, the total equivalent resistance of resistors connected in parallel is given by the formula;

RT = \frac {R1*R2}{R1 + R2}

Substituting into the formula, we have;

75 = \frac {100*R2}{100 + R2}

Cross-multiplying, we have;

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R2 = 7500/25

R2 = 300 Ohms

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