(a) The emf induced in the wire is 0.112 V.
(b) The direction of the current will into the page.
(c) The polarity of A will be positive and L will be negative.
(d) The current flowing through the wire is 0.224 A.
<h3>
EMF induced in the wire</h3>
The emf induced in the wire is calculated as follows;
EMF = BLv
EMF = (8 x 10⁻²) x 0.2 x 7
EMF = 0.112 V
<h3>Direction of the current</h3>
Since, the magnetic field is out of the page, the current will follow counter clockwise and will point into the page.
<h3>Polarity of point A and point L</h3>
The current is flowing counter currently, hence the polarity of A will be positive and L will be negative.
<h3>Current through the wire</h3>
V = IR
I = V/R
I = (0.112)/0.5
I = 0.224 A
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