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Strike441 [17]
4 years ago
3

Earth's tectonic activity is a significant factor that made life on Earth possible because the movement of Earth's crustal plate

s affects _____.
Physics
1 answer:
Genrish500 [490]4 years ago
8 0
Earth's tectonic activity is a significant factor that made life on Earth possible because the movement of Earth's crustal plates affects volcanic activity.

<span>♡♡Hope I helped!!! :)♡♡
</span>
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Which of the following is produced by moving parts of machine?
AnnZ [28]
The answer is Electricity/heat
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During a supernova, the outer layers of a star are blown off and the star's core shrinks down by a factor of 10,000 or more to f
Lana71 [14]

Answer:

a. the core will spin faster.

Explanation:

By law of conservation of angular momentum

(mvR)i= (mvR)f

m= mass of star

v= speed of star

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f= final

since, size(R) of the star is reduced by factor of 10,000 and mass remains the same, the velocity must increase by the same factor to keep the angular momentum conserved.

Hence, a. the core will spin faster.

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4 years ago
Water is flowing in a pipe with a varying cross-sectional area, and at all points the water completely fills the pipe. At point
Salsk061 [2.6K]

Answer:

The fluids speed at a) 0.105\,m^{2}  and b) 0.047\,m^{2} are 2.33\,\frac{m}{s^{2}}  and 5.21\,\frac{m}{s^{2}} respectively

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Explanation:

To solve a) and b) we should use flow continuity for ideal fluids:

\Delta Q=0(1)

With Q the flux of water, but Q is Av using this on (1) we have:

A_{2}v_{2}-A_{1}v_{1}=0 (2)

With A the cross sectional areas and v the velocities of the fluid.

a) Here, we use that point 2 has a cross-sectional area equal to A_{2}=0.105\,m^{2}, so now we can solve (2) for v_{2}:

v_{2}=\frac{A_{1}v_{1}}{A_{2}}=\frac{(0.070)(3.5)}{0.105}\approx2.33\,\frac{m}{s^{2}}

b) Here we use point 2 as A_{2}=0.047\,m^{2}:

v_{2}=\frac{A_{1}v_{1}}{A_{2}}=\frac{(0.070)(3.5)}{0.047}\approx5.21\,\frac{m}{s^{2}}

c) Here we need to know that in this case the flow is the volume of water that passes a cross-sectional area per unit time, this is Q=\frac{V}{t}, so we can write:

A_{1}v_{1}=\frac{V}{t}, solving for V:

V=A_{1}v_{1}t=(0.070m^{2})(3.5\frac{m}{s})(3600s)=882\,m^{3}

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4 years ago
You push a 55.0 kg block to the left with a 245 N force along a frictionless, level surface. The block starts
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It won't stop

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