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horsena [70]
3 years ago
13

Compasses line up with magnetic fields. A compass will line upA. Parallel to magnetic field lines, with the south pole pointing

in the direction of the field.B. Perpendicular to magnetic field lines.C. Parallel to magnetic field lines, with the north pole pointing in the direction of the field.D. Perpendicular to magnetic field lines, in a direction defined by the right-hand rule.
Physics
2 answers:
MA_775_DIABLO [31]3 years ago
5 0

Answer:

C. Parallel to magnetic field lines, with the north pole pointing in the direction of the field.

Explanation:

When a magnet is placed in magnetic field then its North pole and south pole will experience magnetic force in opposite directions.

North pole will tend to move in the direction of magnetic field while south pole has tendency to move opposite to it.

Due to this opposite direction force magnet will experience torque if it is inclined at some angle with magnetic field

Due to this torque magnet will align in the direction of magnetic field such that its north pole will point in the direction of external field while south pole is align opposite to that

Olenka [21]3 years ago
4 0

you are welcome i hope god blesses you today

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The recoil velocity of the astronaut is -0.070 m/s

Explanation:

We can solve this problem by using the principle of conservation of momentum: in fact, in absence of external forces, the total momentum of the astronaut-wrench system must be conserved.

At the beginning, their total momentum is zero:

p=0 (1)

Later, after the astronaut throws the wrench, the total momentum is

p=mv+MV (2)

where

m = 0.725 kg is the mass of the wrench

v = 13.8 m/s is the velocity of the wrench

M = 143 kg is the mass of the astronaut

V is the recoil velocity of the astronaut

Since momentum is conserved, (1) = (2), and so we can find V:

0=mv+MV\\V=-\frac{mv}{M}=-\frac{(0.725)(13.8)}{143}=-0.070 m/s

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5 0
3 years ago
A 7950-kg railroad car travels alone on a level frictionless track with a constant speed of 15.0 m/s . A 2950-kg load, initially
Alchen [17]

The new speed of car is 10.9 m/s

<h3 />

According to the principle of momentum conservation, momentum is only modified by the action of forces as they are outlined by Newton's equations of motion; momentum is never created nor destroyed inside a problem domain.

Mass of the railroad car, m₁ = 7950 kg

Mass of the load, m₂ = 2950 kg

It can be assumed as the speed of the car, u₁ = 15 m/s

Initially, it is at rest, u₂ = 0

Let v is the speed of the car. It can be calculated using the conservation of momentum as :

m_1u_1 + m_2u_2 = (m_1 + m_2) v

v =\frac{m_1u_1}{m_1+m_2}

v = \frac{7950*15}{7950+2950}

v= 10.9 m/s

Therefore, the new speed of care is 10.9 m/s

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5 0
2 years ago
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Lana71 [14]

displacement

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3 years ago
find the image of (4 "-1)" obtained by translating 4 units up followed by a reflection over the y-axis
Harrizon [31]

Answer:(-4,3)

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2 years ago
If a box with a mass of 8.0 kg is sitting on a frictionless surface and experiences an acceleration of 4.0 m/s2 to the right, wh
mr Goodwill [35]

The net force acting on a box of mass 8.0kg that experiences an acceleration of 4.0m/s² is 32N. Details about net force can be found below.

<h3>How to calculate net force?</h3>

The net force of a body can be calculated by multiplying the mass of the body by its acceleration as follows:

Force = mass × acceleration

According to this question, a box with a mass of 8.0 kg is sitting on a frictionless surface and experiences an acceleration of 4.0 m/s2 to the right.

Net force = 8kg × 4m/s²

Net force = 32N

Therefore, the net force acting on a box of mass 8.0kg that experiences an acceleration of 4.0m/s² is 32N.

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4 0
2 years ago
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