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horsena [70]
2 years ago
13

Compasses line up with magnetic fields. A compass will line upA. Parallel to magnetic field lines, with the south pole pointing

in the direction of the field.B. Perpendicular to magnetic field lines.C. Parallel to magnetic field lines, with the north pole pointing in the direction of the field.D. Perpendicular to magnetic field lines, in a direction defined by the right-hand rule.
Physics
2 answers:
MA_775_DIABLO [31]2 years ago
5 0

Answer:

C. Parallel to magnetic field lines, with the north pole pointing in the direction of the field.

Explanation:

When a magnet is placed in magnetic field then its North pole and south pole will experience magnetic force in opposite directions.

North pole will tend to move in the direction of magnetic field while south pole has tendency to move opposite to it.

Due to this opposite direction force magnet will experience torque if it is inclined at some angle with magnetic field

Due to this torque magnet will align in the direction of magnetic field such that its north pole will point in the direction of external field while south pole is align opposite to that

Olenka [21]2 years ago
4 0

you are welcome i hope god blesses you today

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5 points
olga2289 [7]

Answer:

d. 5 ohms

Explanation:

For resistors in parallel, the equivalent resistance is found with:

1/Req = ∑(1/R)

1/R = 1/15 + 1/15 + 1/15

1/R = 3/15

R = 15/3

R = 5

8 0
3 years ago
An atom of calcium-48 and an atom of calcium-47 differ in
anygoal [31]
The 48 and 47 are different atomic masses, this is caused by having a different number of neutrons.
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3 years ago
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An object is launched with an initial speed of 30 m/s at an angle of 60° above the horizontal . What is the maximum height reach
matrenka [14]

Answer:

H = 34.43 m

Explanation:

Given that,

Initial speed of the object, u = 30 m/s

The angle of projection, \theta=60^{\circ}

We need to find the maximum height reached by the object. Let it is H. Using the formula for maximum height reached by the projectile.

H=\dfrac{u^2\sin^2\theta}{2g}\\\\H=\dfrac{(30)^2\times \sin^2(60)}{2\times 9.8}\\\\H=34.43\ m

So, the maximum height reached by the object is 34.43 m.

6 0
3 years ago
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Dafna1 [17]

Answer:

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Andreyy89

Answer:do when the what or them yea cause oh?

Explanation:

8 0
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