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dexar [7]
4 years ago
15

A worker is thinking about two ways to get a box up 1.2 m onto a loading dock. He can use a force of 250 N to lift it straight u

p in 3 s or he can use a force of 75 N to push it up a 4-m-long ramp in 10 s. The two methods have different power outputs. What is the lower power output?
Physics
1 answer:
harina [27]4 years ago
7 0

Answer:

<em>The second option has a lower power output. P=30 W</em>

Explanation:

<u>Mechanical Power </u>

It is a physical magnitude that measures the rate a work W is done over time t.

\displaystyle P=\frac{W}{t}

Since W=F.d

\displaystyle P=\frac{F.d}{t}

The first option means the worker will lift the box by a distance of 1.2 meters in 3 seconds by applying 250 N of force. That produces a power of

\displaystyle P=\frac{(250). (1.2)}{3}=100\ Watt

The second option requires the worker applies 75 N of force and travel a distance of 4 meters for 10 seconds, thus the power is

\displaystyle P=\frac{(75). (4)}{10}=30\ Watt

The second option has a lower power output

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What is the wavelength of an electromagnetic wave?
gizmo_the_mogwai [7]

Answer: (A) The number of waves that pass a point in a certain amount of time.  

Explanation:

Electromagnetic waves are categorized according to their frequency f or, equivalently, according to their wavelength λ = c/f. Visible light has a wavelength range from ~400 nm to ~700 nm.

Frequency: Is the number of waves that pass a certain point in a specified amount of time.

Trough: The low point of the wave cycle.

Wavelength: The distance between two successive peaks.

Electromagnetic wave: One of the waves that are propagated by simultaneous periodic variations of electric and magnetic field intensity.

6 0
2 years ago
The floor of the Atlantic Ocean is spreading slowly. It spreads at the rate of 1 to 10 centimeters per year. Why would it be use
In-s [12.5K]

C because...

Models represent objects, events, and processes in the real world.

Models are often used when an object, event, or process

occurs too slowly or too quickly;

is too small or too large;

is too complicated or too dangerous.

The ocean is spreading at such a slow rate that it would take scientists 50 or more years to collect enough meaningful data from the ocean floor to complete a study. Therefore, scientists use models in order to both predict how the floor will keep spreading and to understand what the ocean floor looked like thousands of years in the past.

8 0
3 years ago
A car starting from rest moves with a constant acceleration of 10 mi/hr2 for 1 hour, then decelerates at a constant 5 mi/hr2 unt
Vinvika [58]

Answer:

The total distance traveled by the car (S) = 15 mi

Explanation:

Total acceleration (a_{1}) = 10 mi / h^{2}

Time (t) = 1 hour

Deceleration (a_{2}) = - 5 mi / h^{2}

From law of speed we know that  V = u + a_{1} t -----------(1)

Where V = Final speed

           u = initial speed and t = time period

Car starts from rest so initial speed is zero so u = 0

Then equation 1 becomes V = a_{1} t = 10 × 1 = 10 mi / h ---------(2)

The distance traveled by the car S_{1} = u t + \frac{1}{2} × a_{1} × t^{2} -------------(3)

Put all the values in equation we get S_{1} = 0 + \frac{1}{2} × 10 × 1^{2}

                                                             S_{1} = 5 mi ---------------(4)

This is the distance traveled by the car in 1 hour.

In second case when car starts decelerates the equation of motion becomes

⇒ V = u - a t -----------(5)

final speed in this case = 0 and initial speed (u) = 10 mi / h

⇒ 0 = 10 - 5 t

⇒ 5 t = 10

⇒ t = 2 hours

Distance traveled by the car in to hours  S_{2} = u t + \frac{1}{2} × a_{2} × t^{2}

⇒ S_{2} = 10 × 2 - \frac{1}{2} × 5 × 2^{2}

⇒ S_{2} = 20 - 10

⇒ S_{2} = 10 mi

This is the distance traveled by the car in the next two hours.

Thus the total distance traveled by the car = S_{1} + S_{2}

⇒ S = 5 + 10 = 15 mi

3 0
3 years ago
If the dielectric constant is 14.1, calculate the ratio of the charge on the capacitor with the dielectric after it is inserted
Lady bird [3.3K]

Answer:

\frac{Q}{Q_0}=1

Explanation:

Capacitance is defined as the charge divided in voltage.

C=\frac{Q}{V}(1)

Introducing a dielectric into a parallel plate capacitor decreases its electric field. Therefore, the voltage decreases, as follows:

V=\frac{V_0}{k}

Where k is the dielectric constant and V_0 the voltage of the capacitor without a dielectric

The capacitance with a dielectric between the capacitor plates is given by:

C=kC_0

Where k is the dielectric constant and C_0 the capacitance of the capacitor without a dielectric. So, we have:

Q=CV\\Q=kC_0\frac{V_0}{k}\\Q=C_0V_0\\Q_0=C_0V_0\\Q=Q_0\\\frac{Q}{Q_0}=1

Therefore, a capacitor with a dielectric stores the same charge as one without a dielectric.

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3 years ago
Use distributive property to express 48+72
Stolb23 [73]

10 ( 6+6 ) = 120

random = abcdefghigklmnopqrstuvwxyz

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