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MrRa [10]
3 years ago
7

Rutherford's gold-foil experiments proved the existence of which of the following?

Chemistry
2 answers:
Anestetic [448]3 years ago
4 0
The answer is the nucleus, because the beam of alpha particles would hit a small, dense positively charged center (nucleus) in the gold foil and bounce back or deflect at angles.
Alexxx [7]3 years ago
3 0
The nucleus i am sure but im not quite positive this is the right answer.
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A substance with a mass of 50.0 g has a temperature change of 40.0
grigory [225]

Answer:

Mass=50.0g

H=670J

change in temperature=40

using. c=h÷m×change in temperature

c=670÷50×40

C=670÷2000

C=0.335jkg-1k-1

7 0
2 years ago
Read 2 more answers
Find the mass of one atom of uranium-235. Recall that the mass in atomic mass units is equal to the mass in grams of one mole of
stiv31 [10]

Answer:

3.90*10^{-25}kg/atom

Explanation:

The molar mass of uranium-235 is 235 g/mol. So one mole of uranium-235 has a mass of 235 g. Put differently 6.022×10^23 atoms of uranium-235 have a mass of 235 g. Knowing that, how can we use that to find the mass of one atom?

mass of one atom = \frac{235 g}{1mol} *\frac{1 mol}{6.022*10^{23}atoms } *\frac{1kg}{1000g}= 3.90*10^{-25}kg/atom

7 0
3 years ago
Can someone help me and fast
jasenka [17]

Answer:

It is likely B.

Explanation:

8 0
3 years ago
PLS HELP what is 2x10^3 in long form
saul85 [17]

Answer:

2x1000 = 2000

Explanation:

10^3 = 10×10×10 = 1000

exponent , the ^3 means multiply the number by itself 3 times, if it was ^4, it would be 4 times and so forth.

another trick for 10s is just put the 1 and the exponents number of 0's after the 1. so in this case, put three 0's: 1,000

6 0
3 years ago
Read 2 more answers
How many millimeters are in 251 cm?
antoniya [11.8K]

Answer:

2510

Explanation:

Since there are 10 milimetres in 1 centimetre, 1 cm = 10mm

There are 10 times as many milimetres as centimetres.

251cm X 10 = mm

251cm = 2510mm

3 0
3 years ago
Read 2 more answers
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