1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
MrRa [10]
3 years ago
7

Rutherford's gold-foil experiments proved the existence of which of the following?

Chemistry
2 answers:
Anestetic [448]3 years ago
4 0
The answer is the nucleus, because the beam of alpha particles would hit a small, dense positively charged center (nucleus) in the gold foil and bounce back or deflect at angles.
Alexxx [7]3 years ago
3 0
The nucleus i am sure but im not quite positive this is the right answer.
You might be interested in
If 3.0 moles of x and 4.0 moles of y react according to the hypothetical reaction below, how many moles of the excess reactant w
Lesechka [4]
Firstly the limiting reactant should be identified. Limiting reactant is the reactant that is in limited supply, the amount of product formed depends on the moles present of the limiting reactant.

the stoichiometry of x to y = 1:2
1 mole of x reacts with 2 moles of y
if x is the limiting reactant, there are 3 moles of x, then 6 moles of y should react, however there are only 4 moles of y. Therefore y is the limiting reactant and x is in excess.
4 moles of y reacts with 2 moles of x 
since there are 3 moles of x initially and only 2 moles are used up, excess amount of x is 1 mol thats in excess.


6 0
3 years ago
What is the main advantage of using ethanol
natka813 [3]

Answer:

Overall, ethanol is considered to be better for the environment than petrol. Ethanol-fuelled vehicles produce lower carbon dioxide emissions, and the same or lower levels of hydrocarbon and oxides of nitrogen emissions.

Explanation:

5 0
3 years ago
How does water heat earth
vovikov84 [41]
The answer is the 3rd one down I think
6 0
3 years ago
Se requieren preparar 1500 ml de una solución al 55% en masa de hidróxido de calcio, sabiendo que la densidad de dicha solución
Masja [62]

Respuesta:

968 g Ca(OH)₂

Explicación:

Paso 1: Calcular la masa de solución

Tenemos 1500 mL de una solución cuya densidad es 1.17 g/mL, es decir, 1 mL de solución tiene una masa de 1.17 g.

1500 mL × 1.17 g/mL = 1.76 × 10³ g

Paso 2: Calcular la masa de hidróxido de calcio en 1.76 × 10³ g de solución

La solución tiene una concentración de 55% en masa de hidróxido de calcio, es decir, cada 100 gramos de solución hay 55 gramos de hidróxido de calcio.

1.76 × 10³ g Solución × 55 g Ca(OH)₂/100 g Solución = 968 g Ca(OH)₂

6 0
3 years ago
What do genotype will appear in boxes 2 and 3?
VMariaS [17]
Tt is the genotype that will appear in boxes two and three.

If you look at the column and row that intersect to form boxes two and three, you will see that they are T and t. That is the best way I can describe it, sorry if it’s confusing.
3 0
3 years ago
Read 2 more answers
Other questions:
  • 30PTS EASY QUESTION
    8·2 answers
  • Write a balanced half-reaction for the reduction of gaseous nitrogen (N2) to aqueous hydrazine (N2H4) in basic aqueous solution.
    9·1 answer
  • A student carries out the precipitation reaction shown below, starting with 0.030 moles of calcium nitrate. The final mass of th
    12·1 answer
  • What’s the difference between the three types on natural radioactivity
    10·1 answer
  • As the pressure on a sample of gas increases, the volume of the sample _____.
    13·2 answers
  • what ere the different types of petrol used in petrol pumps?what is the composition of each and what type of vehicle is each sui
    14·1 answer
  • What mass of hydrochloric acid (in grams) can 2.7 g of sodium bicarbonate neutralize? (Hint: Begin by writing a balanced equatio
    5·1 answer
  • What is the mass of a 120 mL sample of pure silicon with a density of 2.3 g/mL?
    9·1 answer
  • Does anyone know this? help please
    11·1 answer
  • Which option is a physical property of matter?
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!