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Answer:
38.67 N
Explanation:
v = Final velocity = 40 m/s
u = Initial velocity
m = Mass of ball = 0.145kg
s = Displacement of ball = 3 m
Equation of motion
F=ma
∴ Average force that a baseball pitcher's hand exerts on the ball is 38.67 N
Answer
given,
Stress for plastic deformation = 267 MPa
modulus of elasticity = 115 GPa
cross sectional area = 377 mm²
a) maximum load (in N) that may be applied to a specimen
= σ x A
= 267 x 10⁶ x 377 x 10⁻⁶
= 100659 N
b) modulus of elasticity = stress/strain
115 x 10⁹ =
L = 127 mm
115 x 10⁹ =
Δ l = 0.295 mm
maximum length after the stretched = 127 mm + 0.295 mm
= 127.295 mm