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egoroff_w [7]
3 years ago
14

If an object has a mass of 20 kg, what is the force of gravity acting on it on earth? A. 32.67 N B. 2.04 kg C. 1.96 kg D. 196 N

Physics
2 answers:
Brilliant_brown [7]3 years ago
7 0
M=20 kg
g on earth=9.8m sec^-1
F=m*a
F=20*9.8
F=196N
Nimfa-mama [501]3 years ago
4 0

Answer:

D. 196 N

Explanation:

The force of gravity acting on an object located at the Earth's surface is given by:

F=mg

where

m is the mass of the object

g is the acceleration due to gravity

In this problem:

- m=20 kg is the mass of the object

- g = 9.81 m/s^2 is the acceleration due to gravity at Earth's surface

Substituting these data into the formula, we get

F=(20 kg)(9.81 m/s^2)=196.2 N \sim 196 N

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meriva

Answer:

25m/s

Steps:

<em> First, The equation v= u + a * t shows us what we need to find, (the finale velocity). </em>

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Second, we substitute the values given:

v= 9m/s + 4m/s2 * 4s

Last, We calculate the values:

Multiply 4m/s2 * 4s = 16m/s  

Add 9m/s + 16m/s

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<u>Answer:  25m/s</u>

Hope this helps :)

4 0
3 years ago
C. length and mass
Eva8 [605]
Think it would be c, 5.1 g
7 0
3 years ago
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The ___ energy in a mechanical system is determined by adding the potential and kinetic enters together
Svetllana [295]

Answer:

A, total.

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4 0
3 years ago
Thing 1 and Thing 2 push with a force of 2000 N to move a rather small 500 kg elephant 30 m across the kitchen floor. How much w
Amanda [17]

Answer:

60000 J

Explanation:

Assuming the force is applied parallel to the displacement of the elephant, the work done to move it across the floor is

W=Fd

where

F = 2000 N is the force applied

d = 30 m is the displacement of the elephant

Substituting the numbers into the formula, we find

W=(2000 N)(30 m)=60,000 J

3 0
3 years ago
You may have noticed runaway truck lanes while driving in the mountains. These gravel-filled lanes are designed to stop trucks t
kati45 [8]

Answer:

The  coefficient of kinetic friction  \mu_k =  0.724

Explanation:

From the question we are told that

   The  length of the lane is  l =  36.0 \  m

    The speed of the truck is  v  =  22.6\  m/s

     

Generally from the work-energy theorem we have that  

    \Delta KE  =   N  *  \mu_k *  l

Here N  is the normal force acting on the truck which is mathematically represented as

     \Delta KE is the change in kinetic energy which is mathematically represented as

        \Delta KE =  \frac{1}{2} *  m *  v^2

=>     \Delta KE =  0.5  *  m *  22.6^2

=>      \Delta KE =  255.38m

        255.38m =    m *  9.8  *  \mu_k *   36.0

=>     255.38  =    352.8  *  \mu_k

=>   \mu_k =  0.724

 

6 0
3 years ago
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