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3 years ago

If an object has a mass of 20 kg, what is the force of gravity acting on it on earth? A. 32.67 N B. 2.04 kg C. 1.96 kg D. 196 N

Physics

2 answers:

Brilliant_brown [7]3 years ago

7 0

M=20 kg
g on earth=9.8m sec^-1
F=m*a
F=20*9.8
F=196N

Nimfa-mama [501]3 years ago

4 0

Answer:

D. 196 N

Explanation:

The force of gravity acting on an object located at the Earth's surface is given by:

$F=mg$

where

m is the mass of the object

g is the acceleration due to gravity

In this problem:

- m=20 kg is the mass of the object

- g = 9.81 m/s^2 is the acceleration due to gravity at Earth's surface

Substituting these data into the formula, we get

$F=(20 kg)(9.81 m/s^2)=196.2 N \sim 196 N$

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<u>Given the following data:</u>

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Distance, r = 4.2 × 10⁶ m.

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Fc = Fg

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<u>Where:</u>

m is the mass of the satellite.

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v = 1,081.13 m/s.

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Read more on speed here: brainly.com/question/20162935

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2 years ago

A school bus has a mass (including the driver and passengers) of 1.64 times 10^4 kg and is driving north at a speed of 15.2 km/h

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Answer:

Explanation:

Given

mass of bus along with travelers travelling in North direction is $m_1=1.6\times 10^4 kg$

speed of bus towards North $v_1=15.2 km/h\approx 4.22\ m/s$

mass of bus travelling in South direction is $m_2=1.578\times 10^4 kg$

speed of bus $v_2=12.2 km/h\approx 3.38\ m/s$

mass of each Passenger in south moving bus $m_0=64.8 kg$

Momentum of North moving bus

$P_1=m_1\times v_1$

$P_1=1.6\times 10^4\times 4.22$

$P_1=6.768\times 10^4 kg-m/s$

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$P_2=m_2\times v_2+n\cdot m_0\times v_2$

$P_2=(1.578\times 10^4+n\cdot 64.8 )\cdot 3.38$

For total momentum to be towards south

$P_2-P_1$ should be greater than 0

thus for least value of n

$P_2=P_1$

$(1.578\times 10^4+n\cdot 64.8 )\cdot 3.38=6.768\times 10^4$

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Answer:

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$P_{top} = 0.974 \times 10^5$

now we have

$(1.007 - 0.974)\times 10^5 = 1.25 (9.81) h$

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