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ikadub [295]
3 years ago
5

A television has a mass of 19 kg. What is the weight of the television?

Physics
2 answers:
soldi70 [24.7K]3 years ago
7 0
That depends on how far it is from the nearest planet. If it's on the surface of Earth, it weighs (19 kg) x (9.8 m/s^2) = 186.2 newtons.
valkas [14]3 years ago
5 0

Answer:

W = 186.2 N

Explanation:

Weight is defined as the gravitational force on an object which are near the surface of Earth

So it is given by

F = mg

here we know that mass of the television is given as

m = 19 kg

so its weight is given by

W = mg

W = 19 \times 9.8

W = 186.2 N

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FromTheMoon [43]

Answer:

B, A, C, D

Explanation:

i hope it helps. im just kinda guessing.

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3 0
3 years ago
What is the resultant force acting on an object? The first force is 45 N West and the second is 23 N East.
Paul [167]

Answer:

22N West

Explanation:

45-23 because they are in opposite directions.

4 0
3 years ago
A gas is enclosed in a cylinder fitted with a light frictionless piston and maintained at atmospheric pressure. When 3300 kcal o
Tema [17]

Answer

given,

heat added to the gas,Q = 3300 kcal

initial volume, V₁ = 13.7 m³

final volume, V₂ = 19.7 m³

atmospheric pressure, P = 1.013 x 10⁵ Pa

a) Work done by the gas

    W = P Δ V

    W = 1.013 x 10⁵ x (19.7 - 13.7)

    W = 6.029 x 10⁵ J

b) internal energy of the gas = ?

  now,

 change in internal energy

  Δ U = Q - W

    Q = 3300 x 10³ cal

    Q = 3300 x 10³ x 4.186 J

    Q = 1.38 x 10⁷ J

now,

  Δ U = 1.38 x 10⁷  - 6.029 x 10⁵

  Δ U = 1.32 x 10⁷ J

6 0
3 years ago
A boy walked 4m east then 3m south find the displacement
Solnce55 [7]

Answer:

5m

Explanation:

4^{2}+3^{2}=5^{2}\\5^{2}=25

Use the Pythagorean theorem to calculate the long edge of the triangle, which would be his displacement.

3 0
3 years ago
Determine the gravitational field 300km above the surface of the earth. How does this compare to the field on the earth's surfac
Serjik [45]
The strength of the gravitational field is given by:
g= \frac{GM}{r^2}
where
G is the gravitational constant
M is the Earth's mass
r is the distance measured from the centre of the planet.

In our problem, we are located at 300 km above the surface. Since the Earth radius is R=6370 km, the distance from the Earth's center is:
r=R+h=6370 km+300 km=6670 km= 6.67 \cdot 10^{6} m

And now we can use the previous equation to calculate the field strength at that altitude:
g= \frac{GM}{r^2}= \frac{(6.67 \cdot 10^{-11} m^3 kg^{-1} s^{-2})(5.97 \cdot 10^{24} kg)}{(6.67 \cdot 10^6 m)^2}  = 8.95 m/s^2

And we can see this value is a bit less than the gravitational strength at the surface, which is g_s = 9.81 m/s^2.
4 0
3 years ago
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