Answer:

Explanation:
Density can be found by dividing the mass by the volume.

The mass of the water is 50.0 grams.
The volume of the water is 50.0 milliliters.

Substitute the values into the formula.

Divide.

The density of the water is 1.0 grams per milliliter. Also, remember that the density of pure water is always 1.0 g/mL or g/cm³
Answer:

Explanation:
We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.
Mᵣ: 28.01 17.03
N₂ + 3H₂ ⟶ 2NH₃
m/g: 240.0
(a) Moles of NH₃

(b) Moles of N₂

(c) Mass of N₂

Ruler is the answer of this question
Answer:
magnesium has a greater charge, there will be greater attraction between delocalised electrons and the positively charged ion.
Explanation:
I did this once and got it right I hope you get it right too