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Mazyrski [523]
3 years ago
12

What Celsius temperature is equivalent to 298 K?

Chemistry
1 answer:
Anettt [7]3 years ago
4 0

Answer:

25°C

Explanation:

To convert from Kelvin to Celcius we can use this equation:

Temperature in Kelvin - 273 = Temperature in Celcius

298K - 273 = 25°C

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zimovet [89]
D: they have new dna combinations
5 0
3 years ago
Write the value represented by 4.5x10-6 g
monitta

the value represented by 4.5x10-6 g is 0.0000045 g it is a representation  in standard notation

To express enormous figures which are in standard notation like 1,300,000 or exceedingly minuscule quantities like 0.0000000000045, scientists use scientific notation. Scientific notation, also referred to as exponential form, is one of the earliest mathematical techniques. It is well regarded by practitioners. People use scientific notation to handle situations where numbers are too large or too small to be calculated easily. Scientists, engineers, and mathematicians all use this technique. where as standard notation is way writing numbers in normal decimal form. The scientific method id most convenient denoting numbers as the numbers will be either too big or too small.

To learn more about standard notation:

brainly.com/question/10253124

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6 0
1 year ago
Which of these is a compound?<br> A. Na<br> B. Cl<br> C. NaCl<br> D. C
shtirl [24]

Answer:

Option : C

Explanation:

Hope it helps you!

7 0
3 years ago
Read 2 more answers
A patient gets 2.1 L of fluid over 19 hours through an IV. The drop factor is 20 gtt/mL.Calculate the drip rate in drops per min
Aleks [24]
<span>The rate of infusion is 2.1L/19h or 2100mL/19h (as 1L = 100 mL).
       
To convert 19 hours to minutes we multiply as follows:
   
19 hours = (19 hours) x (60 minutes/1 hour) = 1140 minutes
       
So the rate of infusion becomes:
   
2100mL /1140 min
       
In order to converted mL to drops (gtt) we multiply the rate of infusion with the drop factor to get the drip rate:
       
(2100mL/1140min) x (20 gtt/mL) = 36.8 gtt/min</span>
8 0
3 years ago
To run a thin layer chromatography experiment with a chemical substance, begin by marking a horizontal line near the bottom of a
r-ruslan [8.4K]

Answer:

TLC is thin-layer chromatography, a chromatography technique which is used for separating the non-volatile mixtures.

Explanation:

To run a thin layer thin layer chromatography experiment with a chemical substance, begin by marking a horizontal line near the bottom of TLC plate with PENCIL. Place a SMALL spot of the substance onto the line. For the mobile phase add a small amount of SOLVENT at the bottom of TLC chamber. Place the plate in, then COVER the chamber. Once the mobile phase approaches the top of the plate, remove the plate and mark the SOLVENT line. Note the positions of the spot and calculate the Rf if needed.

8 0
3 years ago
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