1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ikadub [295]
3 years ago
8

Use the given probability value to determine whether the sample results could easily occur by​ chance, then form a conclusion. A

study addressed the issue of whether pregnant women can correctly predict the gender of their baby. Among 104 pregnant​ women, 57 correctly predicted the gender of their baby. If pregnant women have no such​ ability, there is a 0.327 probability of getting such sample results by chance. What do you​ conclude? The probability shows that the sample results ▼ could not could have easily occurred by chance. It appears that there ▼ is is not sufficient evidence to conclude that pregnant women can correctly predict the gender of their baby.
Mathematics
1 answer:
Wittaler [7]3 years ago
4 0

Answer:

It appears that there ▼ is is not sufficient evidence to conclude that pregnant women can correctly predict the gender of their baby.

Step-by-step explanation:

The results occur by chance.

There's not enough evidence to show that the pregnant women can predict the gender of the babies. 0.327 probability of getting such sample results by chance means 1-0.325 = 0.675 women are unable to predict the gender.

This 0.675 tells us that more than 67 % of the women are unable to predict the gender.

The other option  is  incorrect .

The probability shows that the sample results ▼ could not have easily occurred by chance.

The probability does not show how the sample results are affected by chance. There' s no increase in the number of trials , there's no evidence of how they guessed.

You might be interested in
Can someone help me with this math homework please!
nadezda [96]

Answer:

250 + 200h = 300 + 180h

200h – 180h = 300 – 250

20h = 50

H = 2.5 credit hours

Step-by-step explanation: Hope this helps and good luck :))

8 0
2 years ago
A lacrosse player throws a ball into the air from a height of 6 feet with an initial vertical velocity of 64 feet per second. Wh
-Dominant- [34]

Answer:

Step-by-step explanation:

I'm going to use calculus to solve this, because it's the simplest way.  

The acceleration due to gravity in feet is the second derivative of the position function.  We will start with the acceleration and work backwards with antiderivatives to get to the position function.

a(t) = -32.  Going backwards and using the fact that the initial vertical velocity is 64 ft/sec, our velocity function is

v(t) = -32t + 64.  Going backwards and using the fact that the initial height of the ball is 6 feet, our position function is

s(t)=-16t^2+64t+6

The first part of this question asks us the maximum height of the ball.  From Physics, we learn that the maximum height of a projectile is reached when the velocity is 0, which happens to be right where the projectile stops for a nanosecond in the air to turn around and come back down.  We set the velocity function equal to 0 and solve for t.

0 = -32t + 64 and

0 = -32(t - 2).  By the Zero Product Property, either -32 = 0 or t - 2 = 0.  It's obvious that -32 does not equal 0, so t - 2 must equal 0.  Solving this for t:

t - 2 = 0 so

t = 2 seconds.  Since the maximum height is reached at a time of 2 seconds, we plug 2 seconds into the position function to get its position at 2 seconds (which is also the max height of the ball).

s(2)=-16(2)^2+64(2)+6 and

s(2) = -64 + 128 + 6 so

s(2) = 70 feet

Now we want to know when the ball will hit the ground.  "When" is a time value, and we know that the height of the ball on the ground is 0, so we sub in a 0 for s(t) and factor the quadratic.

Using the quadratic formula:

t=\frac{-64+/-\sqrt{4096-4(-16)(6)} }{-32} and

t=\frac{-64+/-\sqrt{4480} }{-32} which gives us the 2 solutions

t=\frac{-64+\sqrt{4480} }{-32} and

t=\frac{-64-\sqrt{4480} }{-32}

Plugging into your calculator, the first t = -.0916500 and the second t = 4.091

We all know that time cannot ever be negative, so our t value is 4.09.

Again, from Physics, we know that a projectile reaches it max height at halfway through its travels, so it just goes to follow logically that if it halfway through its travels at 2 seconds, then it will hit the ground at 4 seconds.  And it does!! How awesome is that?!

4 0
3 years ago
Find the slope of the following points (-4,2) and (5,6)
Vlad [161]

Answer:

\huge \frac{4}{9}

Step-by-step explanation:

Given points are: (-4,2) and (5,6)

slope =  \frac{6 - 2}{5 - ( - 4)}  =  \frac{4}{5 + 4}  =  \frac{4}{9}  \\

7 0
2 years ago
Im happy today what about you
VARVARA [1.3K]

Answer:

yess queen

Step-by-step explanation:

why not

8 0
2 years ago
Read 2 more answers
QUESTION 6 of 10: Your plan for your T shirt business calls for you to be able to produce 60,000 screen printed shirts in a mont
Blizzard [7]

Answer:

4

Step-by-step explanation:

I did 60,000 divide by 30 days equal 2000

2000 divide by 500 equals 4

3 0
2 years ago
Read 2 more answers
Other questions:
  • Ryan spent $26.33 on 8 gallons of gas how much would he spend for 20 gallons
    14·2 answers
  • If cos Θ =-4/7 , what are the values of sin Θ and tan Θ?
    5·1 answer
  • The earth's radius is 6.37×106m; it rotates once every 24 hours. you may want to review ( pages 195 - 198) . part a what is the
    9·2 answers
  • Line m passes through the points (-2,7) and (4,-5), as shown below. Which of the following could be the equation of a line that
    11·1 answer
  • X/2-7=9 solve what “x” mean
    5·1 answer
  • Need Help ASAP plz!!!
    8·1 answer
  • Write the subraction problem 604-357. describe how you will subtract to find the difference
    14·2 answers
  • 12.5 x n= 32 What is N???
    6·1 answer
  • I need help asap!! Points of 10. ​
    13·1 answer
  • Can somebody do my math for me ill give you brainlist and 50 points
    10·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!