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ikadub [295]
3 years ago
8

Use the given probability value to determine whether the sample results could easily occur by​ chance, then form a conclusion. A

study addressed the issue of whether pregnant women can correctly predict the gender of their baby. Among 104 pregnant​ women, 57 correctly predicted the gender of their baby. If pregnant women have no such​ ability, there is a 0.327 probability of getting such sample results by chance. What do you​ conclude? The probability shows that the sample results ▼ could not could have easily occurred by chance. It appears that there ▼ is is not sufficient evidence to conclude that pregnant women can correctly predict the gender of their baby.
Mathematics
1 answer:
Wittaler [7]3 years ago
4 0

Answer:

It appears that there ▼ is is not sufficient evidence to conclude that pregnant women can correctly predict the gender of their baby.

Step-by-step explanation:

The results occur by chance.

There's not enough evidence to show that the pregnant women can predict the gender of the babies. 0.327 probability of getting such sample results by chance means 1-0.325 = 0.675 women are unable to predict the gender.

This 0.675 tells us that more than 67 % of the women are unable to predict the gender.

The other option  is  incorrect .

The probability shows that the sample results ▼ could not have easily occurred by chance.

The probability does not show how the sample results are affected by chance. There' s no increase in the number of trials , there's no evidence of how they guessed.

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Which of the following are solutions to the equation below?
snow_lady [41]

Answer:

<h2>E. x = 4</h2>

Step-by-step explanation:

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5 0
3 years ago
Read 2 more answers
A is between C and T and CA =4x + 6, AT =7x-6, and CT =132.
Bingel [31]

Answer:

  • x =12

Step-by-step explanation:

Given

  • A is between C and T
  • CA =4x + 6
  • AT =7x-6
  • CT =132

As per segment addition postulate:

  • CT = CA + AT
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8 0
3 years ago
Which ordered pair is a solution to the system of equations y=x+3 and y=x^2-x
Elenna [48]

For this case we have the following system of equations:

y = x + 3\\y = x ^ 2-x

Equating the equations we have:

x ^ 2-x = x + 3\\x ^ 2-x-x-3 = 0\\x ^ 2-2x-3 = 0

To find the solutions we factor the equation. To do this, we look for two numbers that, when multiplied, result in -3 and when added, result in -2.

These numbers are: -3 and +1

-3 + 1 = -2\\-3 * (+ 1) = - 3

Thus, the factored equation is:

(x-3) (x + 1) = 0

Then, the solutions for the variable "x" are:

x_ {1} = 3\\x_ {2} = - 1

We find the solutions for the variable "y":

y_ {1} = x_ {1} + 3 = 3 + 3 = 6\\y_ {2} = x_ {2} + 3 = -1 + 3 = 2

Thus, the solutions are:

(x_ {1}, y_ {1}): (3,6)\\(x_ {2}, y_ {2}): (-1,2)

ANswer:

(x_ {1}, y_ {1}): (3,6)\\(x_ {2}, y_ {2}): (-1,2)

3 0
4 years ago
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Minchanka [31]
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Answer: $108

Step-by-step explanation:

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80+28= 108

7 0
3 years ago
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