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3 years ago

How many joules of energy do you have if you have 0.45 L of water in a can and you heat the 23C water to 55C site:socratic.org

Chemistry

1 answer:

Bess [88]3 years ago

4 0

Answer:

Q = 60192 j

Explanation:

Given data:

Volume of water = 0.45 L

Initial temperature = 23°C

Final temperature = 55°C

Amount of heat absorbed = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 55°C - 23°C

ΔT = 32°C

one L = 1000 g

0.45 × 1000 = 450 g

Specific heat capacity of water is 4.18 j/g°C

Q = m.c. ΔT

Q = 450 g. 4.18 j/g°C. 32°C

Q = 60192 j

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3 years ago

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4 years ago

Which of the following observations would indicate that a material is a pure substance?

Ira Lisetskai [31]

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6 0

3 years ago

Read 2 more answers

If 0.092J of heat causes a 0.267 degree C temperature change, what mass of water is present?

Thepotemich [5.8K]

Answer:

0.082g

Explanation:

The following data were obtained from the question:

Heat (Q) = 0.092J

Change in temperature (ΔT) = 0.267°C

Specific heat capacity (C) of water = 4.184J/g°C

Mass (M) =..?

Thus, the mass of present can be obtained as follow:

Q = MCΔT

0.092 = M x 4.184 x 0.267

Divide both side by 4.184 x 0.267

M = 0.092 / (4.184 x 0.267)

M = 0.082g

Therefore, mass of water was present is 0.082.

6 0

3 years ago