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strojnjashka [21]
3 years ago
5

Pls it’s urgent

Chemistry
1 answer:
Rainbow [258]3 years ago
4 0

Answer:

0.02 moles.

Explanation:

volume of H₂ gas at R.T.P = 480 cm³

Where

R.T.P = room temperature and pressure

molar volume of gas at = 24000 cm³

no. of moles of hydrogen = ?

Solution:

formula Used

       no. of moles = volume of gas / molar volume

put values in above equation

         no. of moles = 480 cm³ / 24000 cm³/mol

         no. of moles = 0.02 mol

So,

no. of moles of hydrogen in 480 cm³ is 0.02 moles.

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Which correctly lists two characteristics of crystal faces that define crystal systems?
puteri [66]

Answer:

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Explanation:

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6)Explain why a 0.010 M solution of hydrochloric acid, HCl has a pH of 2.00 but a 0.010 M solution of
ExtremeBDS [4]

0.010 M solution of hydrochloric acid, HCl has a pH of 2.00 but a 0.010 M solution of acetic acid, HCH₃COO, is 3.37 is because HCl dissociates more.

<h3>Dissociation</h3>

This is the separation of ions of an ionic compound when it dissolves.

<h3>Hydrogen ion concentration of HCl</h3>

Since 0.010 M solution of hydrochloric acid, HCl has a pH of 2.00 its hydrogen ion concentration is gotten from

pH = -log[H⁺]

So,

[H^{+} ] = 10^{-pH}

So, [H⁺] = 10⁻²

<h3>Hydrogen ion concentration of HCH₃COO</h3>

Also, since 0.010 M solution of acetic acid, HCH₃COO, has a pH of 3.37, its hydrogen ion concentration is gotten from

pH = -log[H⁺]

So,

[H^{+} ] = 10^{-pH}

So, [H⁺] = 10⁻³°³⁷ = 0.000427 = 4.27 × 10⁻⁴

Since the hydrogen ion concentration of HCl is 10⁻² and the hydrogen ion concentration of HCH₃COO is 4.27 × 10⁻⁴, we see that HCl dissociates more than HCH₃COO.

So, 0.010 M solution of hydrochloric acid, HCl has a pH of 2.00 but a 0.010 M solution of acetic acid, HCH₃COO, is 3.37 is because HCl dissociates more.

Learn more about dissociation here:

brainly.com/question/25854432

5 0
2 years ago
A 0.6467-g portion of manganese dioxide was added to an acidic solution in which 1.1701 g of a chloride-containing sample was di
Katen [24]

Answer:

29.39% of AlCl₃ in the sample

Explanation:

Based on the reaction:

MnO₂(s) + 2Cl⁻ + 4H⁺ → Mn²⁺ + Cl₂(g) + 2H₂O

We can find the amount of chloride in solution with the amount of MnO₂ that reacted as follows:

<em>Initial mass MnO₂ = 0.6467g</em>

<em>Recovered mass = 0.3104g</em>

Mass that reacted = 0.6467g - 0.3104g = 0.3363g

<em>Moles MnO₂ -Molar mass: 86.9368g/mol-:</em>

0.3363g * (1mol / 86.9368g) = 3.868x10⁻³ moles MnO₂

<em>Moles Cl⁻:</em>

3.868x10⁻³ moles MnO₂ * (2mol Cl⁻ / 1mol MnO₂) = 7.737x10⁻³ moles Cl⁻

<em>Moles of AlCl₃ and mass -Molar mass AlCl₃: 133.34g/mol-:</em>

7.737x10⁻³ moles Cl⁻ * (1mol AlCl₃ / 3mol Cl⁻) = 2.579x10⁻³ moles AlCl₃

2.579x10⁻³ moles AlCl₃ * (133.34g / mol) =

<em>0.3439g of AlCl₃</em> are present in the sample.

The percent is:

0.3439g of AlCl₃ / 1.1701g * 100 =

<h3>29.39% of AlCl₃ in the sample</h3>

7 0
2 years ago
Someone who’s good with science this is for you btw I’ll brainlist and rate 5 star due today.
alekssr [168]

Answer:

Solid Osmium transition metal reacts with Oxygen gas to produce solid Osmium tetroxide.

Os(s) + 2O₂(g) -> OsO₄(s)

Explanation:

Osmium tetroxide is another way of writing Osmium (VIII) oxide.

Leaving powdered osmium exposed to air in a room will slowly create osmium tetroxide at room temperature.

Similarly, osmium tetroxide vapor will readily be released from a liquid solution at room temperature.

7 0
2 years ago
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