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densk [106]
3 years ago
12

To understand the formula representing a traveling electromagnetic wave.Light, radiant heat (infrared radiation), X rays, and ra

dio waves are all examples of traveling electromagnetic waves. Electromagnetic waves comprise combinations of electric and magnetic fields that are mutually compatible in the sense that the changes in one generate the other.The simplest form of a traveling electromagnetic wave is a plane wave. For a wave traveling in the x direction whose electric field is in the y direction, the electric and magnetic fields are given byE? =E0sin(kx??t)j^,B? =B0sin(kx??t)k^.This wave is linearly polarized in the y direction.1.a. In these formulas, it is useful to understand which variables are parameters that specify the nature of the wave. The variables E0 and B0are the __________ of the electric and magnetic fields.Choose the best answer to fill in the blank.1. maxima2. amplitudes3. wavelengths4. velocitiesb. The variable ? is called the __________ of the wave.Choose the best answer to fill in the blank.1. velocity2. angular frequency3. wavelengthc. The variable k is called the __________ of the wave.1. wavenumber
2. wavelength
3. velocity
4. frequency
Physics
1 answer:
omeli [17]3 years ago
3 0

Answer:

1) Eo and Bo. They are maximum amplitudes. Answer 1 and 2

2) .w is angular frequency. Answer 2

3) k  is wave number. Answer 1

Explanation:

The electromagnetic wave is given by

         E_{y} = E₀ sin (kx –wt)

This is the equation of a traveling wave on the x axis with the elective field oscillating on the y axis

The terms represent E₀ the maximum amplitude of the electric field,

The wave vector

        k = 2π /λ

Angular velocity

       w = 2π f

To answer the questions let's use the previous definitions

1) Eo and Bo. They are maximum amplitudes. Answer 1 and 2

2) .w is angular frequency. Answer 2

3) k is wave number. Answer 1

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2) A Ship has an area of cross - section at the water line of 2000m²
STatiana [176]

Answer:

a. 2 m

b. 0.15 m

Explanation:

(a) By what deck does the ship sink in fresh.

water, when it loads a cargo of 4000 tonnes

We know that the upward force , U on the ship equal the weight of fresh water displaced, W = ρVg where ρ = density of fresh water = 1000 kg/m³, V = volume of water displaced and g = acceleration due to gravity.

So, U = W = ρVg

This upward force must equal the weight of the ship, W' = mg where m = mass of ship = 4000 tonnes = 4000 × 1000 kg = 4 × 10⁶ kg

So. U = W'

ρVg = mg

V = m/ρ = 4 × 10⁶ kg/10³ kg/m³ = 4 × 10³ m³

Now the volume of water displaced equals the volume occupied by the ship floating ship of cross-sectional area, A = 2000 m³ and depth in water h.

So, V = Ah

Thus h = V/A = 4 × 10³ m³/2000 m³ = 2 m

So, the ship sinks to a depth of 2 m in fresh water.

(b) if the ship + Cargo has a displacement tonnage

of 12300 tonnes; by what amount will the ship

rise in the water when it sails from fresh water

into Seawater (density of Sea water - 1025kgm⁻³​

We know that the upward force , U' on the ship in fresh water equals the weight of fresh water displaced, W" = ρV'g where ρ = density of fresh water = 1000 kg/m³, V' = volume of water displaced and g = acceleration due to gravity.

So, U = W" = ρV'g

This upward force must equal the weight of the ship + cargo, W₁ = m₁g where m₁ = mass of ship + cargo = 12300 tonnes = 12300 × 1000 kg = 1.23 × 10⁷ kg

So. U' = W₁

ρV'g = m₁g

V' = m₁/ρ = 1.23 × 10⁷ kg/10³ kg/m³ = 1.23 × 10⁴ m³

Now the volume of water displaced equals the volume occupied by the ship floating ship of cross-sectional area, A = 2000 m³ and depth in fresh water h'.

So, V' = Ah'

Thus h = V'/A = 1.23 × 10⁴ m³/2000 m³ = 6.15 m

So, the ship sinks to a depth of 0.6 m in fresh water.

Also,

We know that the upward force , U" on the ship in sea water equals the weight of sea water displaced, W₂ = ρ'V"g where ρ' = density of sea water = 1025 kg/m³, V"= volume of water displaced and g = acceleration due to gravity.

So, U" = W₂ = ρ'V"g

This upward force must equal the weight of the ship + cargo, W₁ = m₁g where m₁ = mass of ship + cargo = 12300 tonnes = 12300 × 1000 kg = 1.23 × 10⁷ kg

So. U" = W₁

ρ'V"g = m₁g

V" = m₁/ρ' = 1.23 × 10⁷ kg/1.025 × 10³ kg/m³ = 1.2 × 10⁴ m³

Now the volume of water displaced equals the volume occupied by the ship floating ship of cross-sectional area, A = 2000 m³ and depth in sea water h".

So, V" = Ah"

Thus h" = V'/A = 1.2 × 10⁴ m³/2000 m³ = 6 m

So, the ship sinks to a depth of 6 m in fresh water.

So, the rise in height from fresh water to sea water is Δh = h' - h" = 6.15 m - 6 m = 0.15 m

6 0
3 years ago
This graph represents an exothermic reaction. What does it show about the
Zanzabum

The answer is A

Just did it

8 0
3 years ago
1. The first thing to do in the event of brake failure is to a. use the parking brake to stop your carb. pump the brake pedal ra
mars1129 [50]

Answer:

The correct answers are -

1. b. pump the brake pedal rapidly

2. d. all of the above

3. c. your power brakes and power steering won't work very well

4. a. gasoline

5. b. power-assist failure

Explanation:

Brakes help in stopping the vehicle by causing resistance to wheels. IF brake failure it is advised to pump the breaks rapidly in order to cause resistance. Engine failure can be caused by various reasons such as a broken timing gear, no fuel, or getting extremely heated.

In the case of stalling of engine most common effects as power steering not working properly or power brakes not working well. The flooded engine means the engine has too much gasoline that it wont starts.

8 0
3 years ago
Si la velocidad de un bloque unido a un resorte está dada por la ecuación V= 7 cos(8t+0,5π)m/s, determine el módulo de la aceler
vlada-n [284]
Thank you lord lord thank lord lord
5 0
4 years ago
An engine draws energy from a hot reservoir with a temperature of 1250 K and exhausts energy into a cold reservoir with a temper
dimulka [17.4K]

Answer:

The power output of this engine is  P =  17.5 W

The  the maximum (Carnot) efficiency is  \eta_c  = 0.7424

The  actual efficiency of this engine is  \eta _a  = 0.46

Explanation:

From the question we are told that

    The temperature of the hot reservoir is  T_h = 1250 \ K

      The temperature of the cold reservoir  is  T_c  =  322 \ K

     The energy absorbed from the hot reservoir is E_h  = 1.37 *10^{5} \ J

       The energy exhausts into  cold reservoir is  E_c  = 7.4 *10^{4} J

The power output is mathematically represented as

      P  =  \frac{W}{t}

Where t is the time taken which we will assume to be 1 hour =  3600 s  

W is the workdone which is mathematically represented as

      W =  E_h  -E_c

substituting values

       W = 63000 J

So

    P =  \frac{63000}{3600}

    P =  17.5 W

The Carnot efficiency is mathematically represented as

          \eta_c  =  1 - \frac{T_c}{T_h}

         \eta_c  =  1 - \frac{322}{1250}

         \eta_c  = 0.7424

The actual efficiency is mathematically represented as

        \eta _a  =   \frac{W}{E_h}

substituting values

         \eta _a  =  \frac{63000}{1.37*10^{5}}

         \eta _a  = 0.46

     

7 0
4 years ago
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