What are some practical applications for determining the motion of an object?

A transparent oil with index of refraction 1.28 spills on the surface of water (index of refraction 1.33), producing a maximum o

Ad libitum [116K]

Answer:

The thickness of the oil slick is $1.95\times10^{-7}\ m$

Explanation:

Given that,

Index of refraction = 1.28

Wave length = 500 nm

Order m = 1

We need to calculate the thickness of oil slick

Using formula of thickness

$2nt= m\lambda$

Where, n = Index of refraction

t = thickness

$\lambda$ = wavelength

Put the value into the formula

$2\times1.28 \times t=1\times\times500\times10^{-9}$

$t = \dfrac{1\times\times500\times10^{-9}}{2\times1.28 }$

$t=1.95\times10^{-7}\ m$

Hence, The thickness of the oil slick is $1.95\times10^{-7}\ m$

4 0

3 years ago

A 0.40-kg mass, attached to the end of a 0.75-m string, is whirled around in a circular horizontal path. If the maximum tension

hichkok12 [17]

To solve this problem we will apply the concepts given from the circular movement of the bodies for which we have that the centripetal Force is defined as a product between the mass and the velocity squared at the rate of rotation, mathematically this is

$F_c = \frac{mv^2}{r}$

Where,

m = Mass

v = Velocity

r = Radius

Our values are given as

$m = 0.4kg\\r = 0.75m\\F_c = 450N$

Rearranging to find the velocity we have that,

$F_c = \frac{mv^2}{r}$

$v = \sqrt{\frac{F_c * r}{m}}$

$v = \sqrt{\frac{450 * 0.75}{0.4}}$

$v = 29.0474m/s$

Therefore the maximum speed can the mass have if the string is not to break is 29m/s

3 0

3 years ago

Someone pushes on a rock and measures the net force acting on it is 147 N and acceleration to be 7.5m/s2.What is the weight of t

kogti [31]

Some1 pushes u and then u defend your self

7 0

3 years ago

A horizontal beam of electrons initially moving at 4.0×10^7 m/s is deflected vertically by the vertical electric field between o

givi [52]

Answer:

$1.77\times 10^{-7}\ C/m^2$

0.000439077936334 m

Explanation:

q = Charge of electron = $1.6\times 10^{-19}\ C$

E = Electric field = $2\times 10^{4}\ N/C$

$\epsilon_0$ = Permittivity of free space = $8.85\times 10^{-12}\ F/m$

d = Distance between plates = 2 cm (assumed)

m = Mass of electron = $9.11\times 10^{-31}\ kg$

The beam consists of electrons which means it has negative charge this means the upper plates will be positive and the lower plate will be negative.

The direction is upper to lower lower plate.

$\epsilon_0$ = Permittivity of free space = $8.85\times 10^{-12}\ F/m$

Electric flux is given by

$\phi=\epsilon_0E\\\Rightarrow \phi=8.85\times 10^{-12}\times 2\times 10^{4}\\\Rightarrow \phi=1.77\times 10^{-7}\ C/m^2$

The charge per unit area on the plates is $1.77\times 10^{-7}\ C/m^2$

Deflection is given by

$s=\dfrac{1}{2}\dfrac{qE}{m}(\dfrac{d}{v})^2\\\Rightarrow s=\dfrac{1}{2}\dfrac{1.6\times 10^{-19}\times 2\times 10^4}{9.11\times 10^{-31}}(\dfrac{0.02}{4\times 10^7})^2\\\Rightarrow s=0.000439077936334\ m$

The deflection is 0.000439077936334 m

7 0

3 years ago

A thermal insulator separates a warm liquid from a cold liquid. Neglecting the effects of the environment, how will the warm liq

Sindrei [870]

If it;s a good insulator, there'll be no heat transfer warm to cold. So, over time, given the insulation ... nothing should happen ...

5 0

3 years ago