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OLga [1]
3 years ago
14

What are some practical applications for determining the motion of an object?

Physics
1 answer:
Mama L [17]3 years ago
4 0
- rocket science
- automotive research
- space research

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What is the kinetic energy of a 10 kg ball moving at a rate of 2 m/s
Gnoma [55]

Answer:

20 J

Explanation:

KE = ½ mv²

KE = ½ (10 kg) (2 m/s)²

KE = 20 J

7 0
3 years ago
As a football player moves in a straight line [displacement (3.00 mm)i^i^ - (6.50 mm)j^j^], an opponent exerts a constant force
Brilliant_brown [7]

Answer:

Work done, W=(0.378i-1.092j)\ J

Explanation:

Displacement,

d=(3i-6.5j)\ mm\\\\d=(0.003i-0.0065j)\ m

Force, F=(126i+168j)\ N

Work done by the opponent do on the football player is given by :

W=F{\cdot} d\\\\W=(126i+168j){\cdot} (0.003i-0.0065j)\ m\\\\W=(0.378i-1.092j)\ J

So, the work done by the opponent do on the football player is  (0.378i-1.092j)\ J.

4 0
3 years ago
Read 2 more answers
Please help
natali 33 [55]

Answer:

Thermosphere

temperature continue to rise up to 1500*C

Ionosphere

Mesosphere

temperature falls to -93*C

Stratosphere

protective ozone layer

UV radiation causes temperature to rise

Troposphere

78% nitrogen, 21% oxygen

temperature drops from 17 to -52*C

Explanation:

3 0
3 years ago
A constant net force of 345 N is applied to slide a heavy stationary
liubo4ka [24]

Answer:

P = 517.5 [kg*m/s]

Explanation:

We must remember that momentum is defined as the product of force by the time of force duration.

P=F*t

where:

P = momentum [kg*m/s]

F = force [N]

t = time [s]

P=345*1.5\\P=517.5[kg*m/s]

4 0
3 years ago
A car slows down from 27.7 m/s to 10.9 m/s in 2.37 s, what is the acceleration?
larisa [96]

Answer:

Answer. to final velocity 'v' =10.9 m/s in time 't' = 2.37 secs. So acceleration = -7.09 m/sec^2 or, decceleration is 7.09 m/sec^2

Explanation:

4 0
3 years ago
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