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3 years ago

What part of a thunderstorm kills the most people each year?

Physics

2 answers:

Leni [432]3 years ago

7 0

Answer:

Lightning

Explanation:

Lightning strikes are electrical discharges that occur when clouds charge electrically. In a storm, lightning is the factor that kills more people each year. They can be seen through irregular and branched trajectories approximately 2 to 5 cm. For such a discharge to occur it is necessary that the soil has an electrical charge opposite to that contained in the clouds, because this way the attraction between them occurs and finally the discharge is released by the cloud.

Lightning can occur between clouds when they begin within one of these clouds (presenting no direct risk to the ground but to aircraft) and between clouds and soil that can begin both in the cloud and on the ground (with those beginning in the clouds presenting greater soil hazard).

alexandr1967 [171]3 years ago

5 0

Here is the answer. The part of a thunderstorm that kills the <span> most people each year is the LIGHTNING. Thunder is only the sound created and will not hurt anyone, but it is the lightning that can kill anyone who will be struck by it. Hope this answers your question. Have a great day!</span>

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3 years ago

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Ber [7]

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4 years ago

How does 3rd class lever make our work easier

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3 years ago

Read 2 more answers

A completely inelastic collision occurs between two balls of wet putty that move directly toward each other along a vertical axi

Hitman42 [59]

Answer:

the balls reached a height of 4.9985 m

Explanation:

Given the data in the question;

mass one m = 3.8 kg

mass two M = 2.1 kg

Initial velocities

u = 22 m/s

U = { moving downward} = 12 m/s

Now, using the law conservation of linear moment;

mu + MU = v( m + M )

we solve for "v" which is the velocity of the ball s after collision;

v = (mu + MU) / ( m + M )

so we substitute our given values into the equation

v = ( ( 3.8 × 22 ) + ( 2.1 × -12) ) / ( 3.8 + 2.1 )

v = ( 83.6 - 25.2 ) / 5.9

v = 58.4 / 5.9

v = 9.898 m/s

Now, we determine required height using the following relation;

v"² - v² = 2gh

where v" is the velocity at the top which is 0 m/s and g = -9.8 m/s²

0 - v² = 2gh

v² = -2gh

so we substitute

( 9.898 )² = -2 × -9.8 × h

97.97 = 19.6 × h

h = 97.97 / 19.6

h = 4.9985 m

Therefore, the balls reached a height of 4.9985 m

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3 years ago

Which of Newton’s Laws explains why an object originally moving in a circular path will continue in a straight line path if the

Andreas93 [3]

When object is moving in circular path then if suddenly its force reduced to zero then it will move to straight line

This is defined by Newton's First Law

So as per first law of Newton we can say

When there is no net force on an object then it will continue its state of motion in its original state without any change in it.

This is also known as law of inertia

so correct answer will be

Newton's 1st law

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3 years ago