Define
v = volume of a drop per second, cm³/s
The time taken to fill 200 cm³ is 1 hour.
Let V = 200 cm³, the filled volume.
Let t = 1 h = 3600 s, the time required to fill the volume.
Therefore,
The average volume of a single drop is approximately 0.0556 cm³.
Answer: 0.0556 cm³
Answer:
Explanation:
Let the volume below water be v . Then
buoyant force = v d g where d is density of water , g is acceleration due to gravity
= v x 1000 x g
weight of wood piece = volume x density of wood x g
= .6 x 600 x g
for equilibrium while floating
buoyant force = weight
= v x 1000 x g = .6 x 600 x g
v = .36 m²
volume above water or volume exposed = .6 - .36
= .24 m²
When immersed completely ,
buoyant force = .6 x 1000 x 9.8
= 5880 N
weight of wood
= .6 x 600 x g
= 3528 N
buoyant force is more than the weight . In order to equalise them for floating with full volume in water
weight required = 5880 - 3528
= 2352 N.
Answer:
The correct option is;
c. 22.6
Explanation:
The given parameters are;
The hypotenuse of the vector = 32
The angle of the vector = 45°
Therefore, the vector component in the y-axis is given as follows;
Substituting the values from the question gives;
The vector component in the y-axis, 
, is approximately 22.6.
The acceleration of the box is approximately 
Explanation:
According to Newton's second law of motion, the net force acting on the box is equal to the product between its mass and its acceleration:
where
is the net force
m = 12.0 kg is the mass of the box
a is the acceleration
The net force can be written as
where
is the applied forward force
is the friction force
Combining the two equations,
And solving for the acceleration,
Learn more about Newton's second law:
brainly.com/question/3820012
#LearnwithBrainly
Answer:
well for one it can be from drilling or when water starts to breck down the rocks
Explanation:
