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Vera_Pavlovna [14]
3 years ago
10

Organic macromolecules called _______ are insoluble in water

Physics
1 answer:
NikAS [45]3 years ago
3 0

Answer:

lipids are insoluble in water which is why lipids are often found in biological membranes and other waterproof coverings.

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During a sunny afternoon, the sun suddenly seems much less bright than usual. The daylight seems much less intense, as if there
Tatiana [17]

Answer:

D). A sudden change in temperature increased the density of the atmosphere.

Explanation:

The claim that can be made and supported with evidence regarding the temporary decrease in light would be 'a sudden change in temperature will increase the density of the atmosphere.' <u>As the temperature increases, the molecules in the atmosphere begin to move fastly which causes a decrease in atmosphere density while it increases with the fall in temperature. As a result, the intensity of sunlight gets affected due to molecules being heavier and floating in the atmosphere</u>. Thus, <u>option D</u> is the correct answer.

8 0
3 years ago
An alert physics student stands beside the tracks as a train rolls slowly past. He notes that the frequency of the train whistle
Dovator [93]

Answer:The velocity of the train is 3.84m/s

Explanation:

According to the Doppler effect, if the source is moving towards you then the apparent frequency of the sound emitted by the source is higher and if the source is moving away from you then the apparent frequency of the sound emitted by the source is smaller.

This is given by:

fo = V +-Vo/ V +-Vo × source

Where fo= observed frequency

V= velocity of sound

Vo= vo it of the observer

fsource= frequency the source

Given:

Observed frequency of the approaching train fo1= 452Hz

The observed frequency of train= fo2= 442Hz

Velocity of sound= 334m/s

Velocity of source=?

Train approaching the observer is given by:

fo1= V/(V - Vs)× source ...eq1

Train passes the student is given by:

fo2= V/(V - Vs)×source ...eq2

Divide eq1 by eq2

452/442 = (343+Vs)/(343 - Vs)

1.02 =(343+Vs)/(343 -Vs)

Cross multiply

1.02(343- Vs) = 343 + Vs

350.76 - 1.02Vs = 343 + Vs

Collecting like terms

350.76 -343= 1.02Vs+ Vs

7.76 = 2.02Vs

Vs= 7.76/2.02

Vs= 3.84m/s

4 0
3 years ago
At what altitude h above the north pole is the weight of an object reduced to 67% of its earth-surface value? Assume a spherical
lara31 [8.8K]

Answer:

The answer to the question is

At an altitude of 1413 km or 1.222·R above the north pole the weight of an object reduced to 67% of its earth-surface value

Explanation:

We make use of the gravitational formula as follows

F = G\frac{m_{1} m_{2} }{R^{2} }  where

m₁ = mass of the object

m₂ = mass of the earth

d = distance between the two objects and

G = gravitational constant

if at the altitude the weight is reduced to 67 % of its weight on earth then

with all other variables remaining constant, we have

67% F = G\frac{m_{1} m_{2} }{R_{2} ^{2} } =0.67× G×\frac{m_{1} m_{2} }{R_{1} ^{2} }

cancelleing like ternss from  both sides we have

1/R₂² =0.67/R₁² or r₁²/R₂² =0.67 and R₁/R₂ = 0.8185

or R₂ = R₁/0.8185 or 1.222·R = (6.37×10⁶ m)/0.8185 = 7.783×10⁶ m

Hence at an altitude = 1.413×10⁶ m the weight of the object will reduce to 67% its earth-surface value

6 0
3 years ago
PLZ HELP WILL GIVE BRAINLIEST
xxTIMURxx [149]

Answer:

12.7m/s

Explanation:

Given parameters:

Mass of the diver = 77kg

Height  = 8.18m

Unknown:

Final velocity  = ?

Solution:

To solve this problem, we use one of the motion equations.

            v²  = u² + 2gh

v is the final velocity

u is the initial velocity

g is the acceleration due to gravity

h is the height

             v² = 0² + (2 x 9.8 x 8.18)

             v² = 160.3

             v = 12.7m/s

7 0
3 years ago
If you increase the mass but leave the volume the same what happens to the density of the object
atroni [7]
Density is a property of an object or substance that can be described through the correlation of the mass of an object over its volume.

Mathematically, density = mass / volume.
In description, the relationship of density and mass is positively correlated and with volume, inversely.
Since density and mass is positively correlated then if you increase the mass, the density of the object will also increase leaving density and volume the same.

Example:
Mass = 10 g changes to 20
Volume = 5 cm3
Density =?

1. D = m / v
2. D = 10 g / 5 cm3
3. D = 2 g / cm3
4. D = 20 g / 5 cm3
5. D = 4g/cm3



3 0
3 years ago
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