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ella [17]
3 years ago
5

Describe the differences between bonding in an ionic compound and bonding in a covalent molecule.

Chemistry
1 answer:
Fudgin [204]3 years ago
8 0

a covalent bond and an ionic bond. An ionic bond if formed from the transfer of electrons from the outer shell of atoms. ... An example of this is NaCl, where the sodium atom becomes Na+ due to the loss of electrons, and the chlorine atom becomes the negatively charged chloride (Cl-).

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Within which structure of an animal cell does dna replication take place?
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3 0
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What is a moon phase that looks like less than a half circle from earth?
RUDIKE [14]

Answer:

last quarter moon/half moon

Explanation:

4 0
3 years ago
Read 2 more answers
What is the morality of a solution witch composed of 200.12 g HCI in 5.2 L solution?
Dovator [93]

Answer:

1.06 M

Explanation:

200.12/36.46= ans./5.2

grams/atomic mass = ans./volume (L)

5 0
3 years ago
Will these changes increase, decrease, or have no effect on the mean free path of the molecules in a gas sample?
lisabon 2012 [21]
According to the kinetic theory, the mean free path is the average distance a single atom or molecule of an element or compound travels with respect with the other atoms during a collision. The greater the mean free path, the more ideal the behavior of a gas molecule is because intermolecular forces are minimum. To understand which factors affect the mean free path, the equation is written below.

l = μ/P * √(πkT/2m), where
l is the mean free path
μ is the viscosity of the fluid
P is the pressure
k is the Boltzmann's constant
T is the absolute temperature
m is the molar mass

So, here are the general effects of the factors on the mean free path:

Mean free path increases when:
1. The fluid is viscous (↑μ)
2. At low pressures (↓P)
3. At high temperatures (↑T)
4. Very light masses (↓m)

The opposite is also true for when the mean free path decreases. Factors that are not found here have little or no effect.
6 0
4 years ago
A sample of gas in a closed container at a temperature of 100oC and 3 atm is heated to 300oC. What is the pressure of the gas at
Goshia [24]

Answer:

6.14 atm

Explanation:

Initial temperature (T₁) = 100 °C

Initial pressure (P₁) = 4 atm

Final temperature (T₂) = 300 °C

Final pressure (P₂) =?

NOTE: Volume = constant (since the system is a closed system)

Next, we shall convert celsius temperature to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

Initial temperature (T₁) = 100 °C

Initial temperature (T₁) = 100 °C + 273 = 373 K

Final temperature (T₂) = 300 °C

Final temperature (T₂) = 300 °C + 273 = 573 K

Finally, we shall determine the pressure at the highest temperature as follow:

Initial temperature (T₁) = 373 K

Initial pressure (P₁) = 4 atm

Final temperature (T₂) = 573 K

Final pressure (P₂) =?

P₁ / T₁ = P₂ / T₂

4 / 373 = P₂ / 573

Cross multiply

373 × P₂ = 4 × 573

373 × P₂ = 2292

Divide both side by 373

P₂ = 2292 / 373

P₂ = 6.14 atm

Thus, the pressure at the highest temperature is 6.14 atm

6 0
3 years ago
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