Answer: -
Mass of Hydrated KAl(SO₄)₂ = 2.0 g
Molar mass of anhydrous KAl(SO₄)₂ = 258.20 g/ mol
Mass of of anhydrous KAl(SO₄)₂ = mass of the 2nd heating = A
The mass of water released = mass of the Aluminum Cup + 2.0 grams of KAl(SO₄)₂ - mass of the 2nd heating
= H g
Moles of water released = 
Moles of anhydrous KAl(SO₄)₂ = 
Required ratio = 
Answer:
9
Explanation:
a significant number is a non zero number or exponent or a zero between numbers
Should be B. An extended period of rain
Answer: V1 = 45.6 ml
Explanation:
This is a dilution process whereby the concentration of phosphate in the solution is being reduced from 4.5m to 2m. Meanwhile. In a concentration process, the concentration of the phosphate solution will be increased. It can be achieved by removing solvents.
The dilution equation will be used. The equation is as follows:
M1V1 = M2V2 where
V1 = Initial volume of phosphate solution.
M1 = Initial concentration of phosphate solution.
V2 =Final volume of phosphate solution.
M2 = Final concentration of phosphate solution .
From the information given,
M1 = 4.5
V1 = ?
M2 = 2.0
V2 = 80
4.5 × V1 = 2×80
4.5V1 = 160
V1 = 160/4.5
= 35.6 ml
