Answer:
In order of least to greatest- 99%, -9.9, sqaure root of 80, 1/9, sqaure root of 9, 19%
Step-by-step explanation:
Answer:
If the x is multiplication, then the statement is false. If the x is a variable, it is also false.
Step-by-step explanation:
The 2 numbers can be: 0.0041 and 0.0045
3. First factor
as a difference of cubes:

For the remaining group, apply the double angle identity.



![\implies4(\cos^6A-\sin^6A)=\cos2A[(1+2\cos2A+\cos^22A)+(1-\cos^22A)+(1-2\cos2A+\cos^22A)]](https://tex.z-dn.net/?f=%5Cimplies4%28%5Ccos%5E6A-%5Csin%5E6A%29%3D%5Ccos2A%5B%281%2B2%5Ccos2A%2B%5Ccos%5E22A%29%2B%281-%5Ccos%5E22A%29%2B%281-2%5Ccos2A%2B%5Ccos%5E22A%29%5D)

5. seems rather tricky. You might want to post another question for that problem alone...
6. Factorize the left side as a sum of cubes:

From here we have to prove that

We can write everything in terms of sine:
(double angle identity)
(angle sum identity)
After some simplifying, we're left with showing that

or

This last equality follows from what you could the triple angle identity for sine,

Answer:
irrational numbers
Step-by-step explanation:
i think that is the only one