Answer:
1.31498 kg
0.72050 s
0.72050 s
Explanation:
m = Mass of block
g = Acceleration due to gravity = 9.81 m/s²
k = Spring constant = 100 N/M
x = Displacement = 0.129 m
The force balance is

The mass of the block is 1.31498 kg
Time period is given by

The period of oscillations is 0.72050 s
The time period does not depend on the acceleration due to gravity. It varies with the mass and the spring constant.
Hence, the time period would be the same
Answer:
a) speed when Jack sees the pot : 12.92 meters per second
b) height difference 163.115 meters
Explanation:
First to calculate te initial speed we use the acceleration formula:
a= v1-v0/t
Acceleration being gravity's acceleration (9.8 m/s^2)
v1 being the speed when Jill sees the pot
v0 when Jack sees it
and t the time between
Solving for v0 it would be
v1 - a*t = v0
replacing

For the second question we use the position formula setting y0 and t0 as the position and time when jack sees the pot. (and setting the positive axis downward I.E. one meter below jack would be 1m not -1m)
The formula is

replacing

Answer:
43.83
N
Explanation:
Given that,
The mass of an object, m = 34.4 kg
The coefficients of static and kinetic frictions for plastic on wood are 0.53 and 0.40, respectively.
The force of static friction,

The force of kinetic friction,

Net force acting on the object is :
F = 178.67-134.84
= 43.83 N
Hence, this is the required solution.
Answer:
D. It is relatively inert.
Explanation:
The original vertical velocity = 0 (because the stone was dropped).
Assume that air resistance may be ignored.
Let x = the distance the stone drops in time t.
Then
x = 0*t + (1/2)*(9.8 m/s²)*(t s)²
= 4.9t² m
The height of the stone above ground is
h(t) = 900 - 4.9t² m
Answer: h(t) = 900 - 4.9t²