Answer:
I. dipole-dipole
III. dispersion
IV. hydrogen bonding
Explanation:
Intermolecular forces are weak attraction force joining nonpolar and polar molecules together.
London Dispersion Forces are weak attraction force joining non-polar and polar molecules together. e.g O₂, H₂,N₂,Cl₂ and noble gases. The attractions here can be attributed to the fact that a non -polar molecule sometimes becomes polar because the constant motion of its electrons may lead to an uneven charge distribution at an instant.
Dispersion forces are the weakest of all electrical forces that act between atoms and molecules. The force is responsible for liquefaction or solidification of non-polar substances such as noble gas an halogen at low temperatures.
Dipole-Dipole Attractions are forces of attraction existing between polar molecules ( unsymmetrical molecules) i.e molecules that have permanent dipoles such as HCl, CH3NH2 . Such molecules line up such that the positive pole of one molecule attracts the negative pole of another.
Dipole - Dipole attractions are more stronger than the London dispersion forces but weaker than the attraction between full charges carried by ions in ionic crystal lattice.
Hydrogen Bonding is a dipole-dipole intermolecular attraction which occurs when hydrogen is covalently bonded to highly electronegative elements such as nitrogen, oxygen or fluorine. The highly electronegative elements have very strong affinity for electrons. Hence, they attracts the shared pair of electrons in the covalent bonds towards themselves, leaving a partial positive charge on the hydrogen atom and a partial negative charge on the electronegative atom ( nitrogen in the case of CH3NH2 ) . This attractive force is know as hydrogen bonding.
The results of this experiment gave Rutherford the means to arrive at two conclusions: one<span>, an atom was much more than just empty space and scattered electrons and </span>two<span>, an atom must have a positively charged center that contains most of its mass (which Rutherford termed as the </span>nucleus<span>).
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Answer: a ) NaCl
b) No compound.
Explanation:
Atomic number of A is 11 , thus it is sodium. It has electronic configuration of 2,8,1 and thus has 1 valence electron and can form
.
Atomic number of B is 18 , thus it is argon. It has electronic configuration of 2,8,8 and thus it is an inert gas.
Atomic number of C is 1 , thus it is hydrogen. It has electronic configuration of 1. It can only share electrons.
Atomic number of D is 17 , thus it is chlorine. It has electronic configuration of 2,8,7 and thus has 7 valence electron and can form
.
a) A and D :
Here Sodium is having an oxidation state of +1 called as
cation and anion is
. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral ![NaCl](https://tex.z-dn.net/?f=NaCl)
b) B and C
As B is an inert gas , it wont combine with C.
Answer: the answer would be B
Answer:6 valence electrons
and
one valence electron
Explanation: