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OleMash [197]
3 years ago
12

Among the four ecosystems, is the most diverse. In the second ecosystem, there are 4 species of producers, 8 primary consumers,

10 secondary consumers, and 10 tertiary consumers. If the number of species of primary consumers in the second ecosystem increases to 20, there will be .
Chemistry
2 answers:
Julli [10]3 years ago
5 0

Among the four ecosystems, ecosytem 3 is the most diverse. In the second ecosystem, there are 4 species of producers, 8 primary consumers, 10 secondary consumers, and 10 tertiary consumers. If the number of species of primary consumers in the second ecosystem increases to 20, there will be fewer producers in the ecosystem.

Rama09 [41]3 years ago
4 0

Species will be four secondary and tertiary consumers will be 25

Explanation-

Given in the question the number of species is 4 then it will have 8 primary 10 secondary and 10 tertiary consumers.  If this number of primary consumers increases from 8 to 20 consumers then the number of species involved would be 10 { 4x20/8 }

Number of secondary consumers would also be increased and increased value would be 25 { 10x20/8 } then again comes the tertiary number of consumer which also increases. The number of tertiary consumers will increase to 25 { 10x20/8} same as secondary.  

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<h3>Answer:</h3>

             Molar Mass =  56 g.mol⁻¹

<h3>Explanation:</h3>

Data Given:

                   Mass  =  5.00 μg  =  5.0 × 10⁻⁶ g

                   Number of Molecules  =  5.38 × 10¹⁶ Molecules

Step 1: Calculate Moles of 1-Butene:

                      As we know one mole of any substance contains 6.022 × 10²³ particles (atoms, ions, molecules or formula units). This number is also called as Avogadro's Number.

The relation between Moles, Number of Particles and Avogadro's Number is given as,

                          Number of Moles  =  Number of Particles ÷ 6.022 × 10²³

Putting values,

                          Number of Moles  =  5.38 × 10¹⁶ Molecules ÷ 6.022 × 10²³

                          Number of Moles  =  8.93 × 10⁻⁸ Moles

Step 2: Calculate Molar Mass of 1-Butene:

As,

                          Mole  =  Mass ÷ M.Mass

Solving for M.Mass,

                          M.Mass  =  Mass ÷ Mole

Putting values,

                          M.Mass  =  5.0 × 10⁻⁶ g ÷ 8.93 × 10⁻⁸ mol

                          M.Mass =  55.99 g.mol⁻¹ ≈ 56 g.mol⁻¹

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Explanation:

Here, we want to know which of the options represent the least number of molecules;

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Number of moles = mass/molar mass

Then from the number of moles, we can calculate the number of molecules by multiplying the number of moles by 6.02 * 10^23 molecules

Let’s proceed;

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