Question

4. If 0.130 g of p-aminophenol is allowed to react with excess acetic anhydride, what is the theoretical yield of acetaminophen in moles? In grams?

Answer 1

Hey There!

p-aminophenol (109.13 g/mol) + Ac2O (102.09 g/mol) ---> acetominophen (151.16 g/mol)

next, since you already know your limiting reactant (p-aminophenol), convert it to mols  :

0.130 g / (109.13 g/mol) = 0.00119 moles

now that's your theoretical max, since its a 1:1 mol ratio, so multiply by the new molecular weight. :

0.00119  * 151.16  = 0.180 g

Hope that helps!