It does<span>, however, change the </span>mass<span> of the nucleus. </span>Adding<span> or removing </span>neutrons<span>from the nucleus are how isotopes are created. Protons carry a positive electrical charge and they alone determine the charge of the nucleus.</span>
It’s #2 because I saw on edigunity 2020
Answer:
4.2 m
Explanation:
The energy (E) of the selector region of the spectrometer is:
E = v*B (equation 1)
Where v is the velocity, and B the magnetic field.
The force with which particle forms a curved path can be calculated by:

Where r is the radius of the particle, m is the mass, and q the electric charge. So:

For equation 1: v = E/B, so:

The two species will be separated by Δr = 0.42 mm
Δr = Δm*E/(q*B*B')
E/(q*B*B') = r/m
Δr = Δm*r/m
r = m*Δr/Δm
r is the large of curvature, m is the avarege mass = (28.0106 + 28.0134)/2 = 28.012:
r = (28.012*0.42)/(28.0134 - 28.0106)
r = 11.76504/(0.0028)
r = 4201.8 mm
r = 4.2 m
Answer:
Trimethylacetaldehyde
Explanation:
For the <u>unknow compound</u> we have a molar mass of 86 g/mol. We have an even value for the mass, so the compound does <u>not have nitrogen</u> and we can have several posibilities:
A) 
B) 
C) 
D) 
If we check the IR info a signal in 1730 cm-1 appears, this indicates that we have an <u>oxo group</u> (C=O). So, the D option can be discarded. The groups that can have the oxo group are: Carboxylic acids, <u>Ketones and aldehydes</u>.
We don have a signal in 3000 cm-1, so the carboxylic acid can be discarded. Now, is we check the info for the 1H NMR we only have 2 signals. If we only have 2 we will have a very<u> symmetric compound</u>.
By trial an error the find the compound <u>Trimethylacetaldehyde</u> (Figure 1).