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balu736 [363]
3 years ago
13

What is the difference between intensive & extensive phyiscal properties? ​

Chemistry
1 answer:
iVinArrow [24]3 years ago
3 0

Answer:

Extensive properties, such as mass and volume, depend on the amount of matter being measured. Intensive properties, such as density and color, do not depend on the amount of the substance present. Physical properties can be measured without changing a substance's chemical identity.

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Write the balanced equation for the burning of nonane, c9h20, in air.
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C9H20 + 14O2 --> 9CO2 + 10H2O
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Give Me a simple definition for Acids.
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an acid is a substance which produces hydrogen ions as the only as the only positive ion when dissolved in water.

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To determine the specific heat capacity of copper, Alyssa performed an investigation by which she dropped a heated piece of copp
user100 [1]

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0.446

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2 years ago
A gas has a volume of 5.0 L at a pressure of 50 KPa. What happens to the volume when the pressure is increased to 125?
Alexeev081 [22]
The volume becomes two. You have to use the equation P1 x V1 = P2 x V2 
P is pressure and V is volume.
P1 = 50     P2 = 125
V1 = 5       V2 = v (we don't know what it is)
Then set up the equation:
50 times 5 = 125 times v
250 = 125v
the divide both sides by 125 and isolate v
2 = v
Therefore the volume is decreased to 2.
Also, Boyle's Law explains this too: Volume and pressure are inversely related, This means that when one goes up the other goes down (ie when pressure increases volume decreases and vice versa). Becuase the pressure went up from 50 KPa tp 125 KPa the volume had to decrease.

7 0
3 years ago
A gas balloon has a volume of 106.0 liters when the temperature is 25.0 °C and the pressure is 740.0 mm Hg. What will its volume
ipn [44]

Answer : The final volume of gas will be, 103.3 L

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 740.0 mmHg  = 98.4 kPa

Conversion used : (1 mmHg = 0.133 kPa)

P_2 = final pressure of gas = 99.3 kPa

V_1 = initial volume of gas = 106.0 L

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 25.0^oC=273+25.0=298K

T_2 = final temperature of gas = 20.0^oC=273+20.0=293K

Now put all the given values in the above equation, we get:

\frac{98.4kPa\times 106.0L}{298K}=\frac{99.3kPa\times V_2}{293K}

V_2=103.3L

Therefore, the final volume of gas will be, 103.3 L

8 0
3 years ago
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