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svetoff [14.1K]
2 years ago
12

Which statement about covalent bonds is true

Physics
2 answers:
g100num [7]2 years ago
7 0
In covalent bonds the atoms share electrons.
marusya05 [52]2 years ago
4 0

Answer:c

Explanation:

i did the usatestprep

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Can someone help me plz<br>it's a glass bell jar and to vacuum pump
Nata [24]
A) the pump removes air from the enclosure. foam absorbs vibrations from the clock
b) result is that as the air is taken out by pump, the sound of alarm reduces and eventually becomes zero. so, you cant hear the alarm ringing.
c) conclusion is that sound cant travel in vaccum and it requires a medium to travel.
7 0
3 years ago
A hand pump is being used to inflate a bicycle tire that has a gauge pressure of 41.0 lb/in2. If the pump is a cylinder of lengt
damaskus [11]

Answer:

L - h = 12.3672 in

Explanation:

Given

P = 41.0 lb/in² = 41 P.S.I

L = 16.8 in

A = 3.00 in²

h = ?

In order that air flows into the tire, the pressure in the pump must be more than the tire pressure,  41.0  PSI.

We assume that air follows ideal gas equation, the temperature of the compressed air remains constant as the piston moves down. Taking one atmospheric pressure to be  14.6959  P.S.I , we can use the ideal gas equation

P*V = n*R*T

As number of moles of air do not change during its compression in the pump, n*R*T of the gas equation is constant. Therefore we have

P₁*V₁ = P₂*V₂    ⇒    V₂ = P₁*V₁ / P₂

where  

1  and  2  are initial and final states respectively,

V₁ = A*L = (3.00 in²)*(16.8 in)   ⇒   V₁ = 50.4 in³

P₁ = 14.6959  P.S.I

P₂ = P₁ + P = (14.6959 lb/in²) + (41.0 lb/in²) = 55.6959 lb/in²

Inserting various values we get

V₂ = (14.6959  P.S.I)*(50.4 in³) / (55.6959 lb/in²)

⇒  V₂ = 13.2985 in³

Length of pump, measured from bottom, this volume corresponds to is

h = V₂ / A  = (13.2985 in³) / (3.00 in²)

⇒  h = 4.4328 in

Piston must be pushed down by more than

L - h = 16.8 in - 4.4328 in = 12.3672 in

4 0
3 years ago
Hi guys. Help with any of these questions! Pressure in physics year 7 :) <br> Thanks!
SVEN [57.7K]

Answer:

2 a) it is less dense than the water

2 b) it is more dense than the water

3 a ping pong ball is hollow and less dense than the water so it quickly bounces up to the surface of the water

5 0
3 years ago
During a marathon race, a runner’s blood flow increases to 10.0 times her resting rate. Her blood’s viscosity has dropped to 95.
Phoenix [80]

To solve the problem it is necessary to apply the equations related to the Poiseuilles laminar flow law, with which the stationary laminar flow ΦV of an incompressible and uniformly viscous liquid (also called Newtonian fluid) can be determined through a cylindrical tube of constant circular section. Mathematically this can be expressed:

Q = \frac{\Delta P \pi r^4}{8\eta l}

Where:

\eta_i = are the viscosities of the concrete before and after the increase

l = Length of the vessel

r_1, R_2 = Radio of the vessel before and after the increase

\Delta P= Change in the pressure

Q_{1,2} = The rates of flow before and after he increase

Our values are given as:

Q_2 = 10Q_1 \rightarrow 10 times her resting rate

\eta_2 = 0.95\eta_1 95% of its normal value

\Delta P_2 = 1.5\Delta P_1 Increase of 50%

Plugging known information to get

Q_1 = \frac{\Delta P \pi r^4}{8\eta l}

Q_1 8\eta_1 l = \Delta P_1 \pi r_1^4

r_1^4 = \frac{Q_1 8\eta_1 l}{\Delta P_1 \pi}

r_1 = (\frac{Q_1 8\eta_1 l}{\Delta P_1 \pi})^{1/4}

r_2 = (\frac{Q_2 8\eta_2 l}{\Delta P_2 \pi})^{1/4}

r_2 = (\frac{10Q_18 \times 0.95\eta_1 l}{1.5\Delta P_1 \pi})^{1/4}

r_2 = 1.586r_1

Therefore the factor of average radio of her blood vessels increased is 1.589 the initial factor after the increase.

7 0
3 years ago
A dump truck and a little toy matchbox car have the same velocity. which one has the greater momentum?
Zina [86]
That would be the dump truck. Momentum depends on how heavy a certain object is in motion. The more weight it has the harder it is to stop.
4 0
3 years ago
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