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Tamiku [17]
2 years ago
7

What is the correct displacement for the following vectors: 4 km south, 2 km north, 5 km south, and 5 km north? 2 km south 16 km

total 11 km west 6 km south
Physics
1 answer:
lesantik [10]2 years ago
6 0

<u>Answer:</u>

The correct answer option is: 2 km South.

<u>Explanation:</u>

We are to find out the displacement for the given vectors:

- 4 km south,

- 2 km north,

- 5 km south; and

- 5 km north

So starting off with the vector going 4 km south we have a displacement of 4 km south. Then it goes 2 km so we are left with 4 - 2 = 2 km south.

Next, it goes 5 km south so we will have a displacement of 2 + 5 = 7 km south. Then again it goes 5 km north so we are left with a displacement of 7 - 5 = 2 km South.

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The final velocity of the block A will be 2.5 m/sec. The principal of the momentum conversation is used in the given problem.

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According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.

In a given concern, mass m₁ is M, mass m₂ is 3M. Initial speed for the mass m₁ and  m₂ will be u₁=5 and u₂=0 m/s respectively,

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To learn more about the law of conservation of momentum, refer;

brainly.com/question/1113396

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