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avanturin [10]
3 years ago
15

2. When an object moves in a circular path, it accelerates toward the center of the circle

Physics
2 answers:
Marianna [84]3 years ago
8 0
The answer is “C” centripetal force
hammer [34]3 years ago
6 0

Answer:

the answer is c. centripetal force

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A 400 kg satellite is in a circular orbit at an altitude of 500 km above the Earth's surface. Because of air friction, the satel
scoundrel [369]

Answer:

E = 1.45 x 10⁹ J = 1.45 GJ

Explanation:

According to the law of conservation of energy:

Potential Energy Lost by Satellite = Kinetic Energy + Internal Energy

mgh = \frac{1}{2} mv^2 + E\\\\E = mgh - \frac{1}{2} mv^2

where,

E = Internal Energy = ?

m = mass = 400 kg

g = acceleration due to gravity = 9.81 m/s²

h = height = 500 km = 500000 m

v = speed on ground = 1.6 km/s = 1600 m/s

Therefore,

E = (400\ kg)(9.81\ m/s^2)(500000\ m)-\frac{1}{2} (400\ kg)(1600\ m/s)^2\\E = 1.962\ x\ 10^9\ J - 0.512\ x\ 10^9\ J

<u>E = 1.45 x 10⁹ J = 1.45 GJ</u>

8 0
3 years ago
6 A simple ideal Rankine cycle with water as the working fluid operates between the pressure limits of 4 MPa in the boiler and 2
makvit [3.9K]

To solve this problem we will start by differentiating the values in each of the states of matter. Subsequently through the thermodynamic tables we will look for the values related to the entropy, enthalpy and respective specific volumes. Through the relationship of Power defined as the product between mass and enthalpy and mass, specific volume and pressure, we will find the energetic values in the two states investigated. We will start defining the states

State 1

T_1 = 700\°C

P_1 = 4 Mpa

From steam table

h_1 =3906.41 KJ/Kg

s_1 = 7.62 KJ/Kg.K

Now

s_1 = s_2 = 7.62 KJ/Kg.K <em>As 1-2 is isentropic</em>

State 2

P_2 = 20 Kpa

s_2 = 7.62 KJ/Kg \cdot K

From steam table

h_2 = 2513.33 KJ/Kg

PART A) The power produced by turbine is the product between the mass and the enthalpy difference, then

Power = m \times (h_1-h_2)

P = (50)(3906.41 - 2513.33)

P = 69654kW

b) Pump Work

State 3

P_3 = 20 Kpa

\upsilon= 0.001 m^3/kg

The Work done by the pump is

W= m\upsilon \Delta P

W = (50)(0.001)(4000-20)

W = 199kJ

5 0
3 years ago
what is the largest and smallest possible resultant force of two force with magnitude of 41N and 14N​
MArishka [77]

Explanation:

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8 0
3 years ago
When an electron moves from a lower to a higher energy level the electron?
vladimir1956 [14]
A photon is absorbed

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8 0
4 years ago
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Describe the mirror formula for a concave mirror in a shortcut way​
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Answer:

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Explanation:

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