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elena-14-01-66 [18.8K]
3 years ago
10

Electromagnetic radiation with a wavelength of 525 nm appears as green light to the human eye. The energy of one photon of this

light is____________.
A) 1.04*10^-22

B)1.4*10^-31

C) 2.64*10^18

D) 3.79*10^-28

E) 3.79*10^-19
Chemistry
1 answer:
Sedbober [7]3 years ago
3 0

<u>Answer:</u> The energy of one photon of the given light is 3.79\times 10^{-19}J

<u>Explanation:</u>

To calculate the energy of one photon, we use Planck's equation, which is:

E=\frac{hc}{\lambda}

where,

\lambda = wavelength of light = 525nm=5.25\times 10^{-7}m        (Conversion factor:  1m=10^9nm  )

h = Planck's constant = 6.625\times 10^{-34}J.s

c = speed of light = 3\times 10^8m/s

Putting values in above equation, we get:

E=\frac{6.625\times 10^{-34}J.s\times 3\times 10^8m/s}{5.25\times 10^{-7}mm}\\\\E=3.79\times 10^{-19}J

Hence, the energy of one photon of the given light is 3.79\times 10^{-19}J

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The diagram below shows the atoms involved in forming table salt. Which statement best describes what happens next ?
Ghella [55]

An ionic compound is composed of ionic bonds that are formed by transfer of electrons from one atom to the other. The atom that loses electrons acquires a positive charge (cation) while that which gains electrons acquires a negative charge.

In the case of sodium chloride; Sodium Na has 1 electron in its outer orbital while Chlorine Cl has 7 electrons. Thus, Cl requires 1 electron to complete its octet. This electron is donated by Na.

Thus, NaCl is essentially, Na⁺Cl⁻

Ans D) Chlorine becomes an anion by gaining an electron from sodium

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3 years ago
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Determine the concentration of a solution made by dissolving 1.40grams NaCL in enough water to make 30.0mL of solution.
KiRa [710]

Answer: 0.8M

Explanation:

Given that,

Amount of moles of NaCl (n) = ?

Mass of NaCl in grams = 1.40 g

For molar mass of NaCl, use the molar masses:

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Chlorine, Cl = 35.5g

NaCl = (23g + 35.5g)

= 58.5g/mol

Since, amount of moles = mass in grams / molar mass

n = 1.40g / 58.5g/mol

n = 0.024 mole

Now, given that:

Amount of moles of NaCl (n) = 0.024

Volume of NaCl solution (v) = 30.0mL

[Convert 30.0mL to liters

If 1000 mL = 1L

30.0mL = 30.0/1000 = 0.03L]

Concentration of NaCl solution (c) = ?

Since concentration (c) is obtained by dividing the amount of solute dissolved by the volume of solvent, hence

c = n / v

c = 0.024 mole / 0.03 L

c = 0.8 M (0.8M means concentration is in moles per litres)

Thus, the concentration of the solution is 0.8M

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3 years ago
A container was found in the home of the victim that contained 120 g of ethylene glycol in 550 g of liquid. How many drinks, eac
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Answer:

0.432 drinks are toxic

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The toxic dose of ethylene glycol is 0.1 mL per kg body weight (mL/kg). In grams (Density ethylene glycol = 1.11g/mL):

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If the victim weighs 85kg, its letal dose is:

85kg * (0.111g/kg) = 9.435g of ethylene glycol

Using the concentration of ethylene glycol in the liquid:

9.435g of ethylene glycol * (550g liquid / 120g ethylene glycol) = 43.2g of liquid are toxic.

The drinks are:

43.2g of liquid * (1 drink / 100 g) =

<h3>0.432 drinks are toxic</h3>
5 0
3 years ago
1.
german

Order of metals from least reactive to most reactive: B <C <A <D

<h3>Further explanation</h3>

Reducing agents are substances that experience oxidation  

Oxidizing agents are substances that experience reduction

The metal activity series is expressed in voltaic series  

<em>Li-K-Ba-Ca-Na-Mg-Al-Mn- (H2O) -Zn-Cr-Fe-Cd-Co-Ni-Sn-Pb- (H) -Cu-Hg-Ag-Pt-Au  </em>

The more to the left, the metal is more reactive (easily release electrons) and the stronger reducing agent  

The more to the right, the metal is less reactive (harder to release electrons) and the stronger oxidizing agent

So that the metal located on the left can push the metal on the right in the redox reaction  

Let's analyze the statement in the problem

I. Only A, C and D react with 1 mol/L HCl to give H₂(e)

M + HCl ⇒ MCl + H₂(MCl : alkali, MCl₂ : alkaline earth)

A, C and D can react with 1 mol / L HCl, meaning metals A, C and D are located to the left of element H (more reactive), and B in the right of element H

II. When A is added to solutions of the other metal ions, metallic B and C are  formed but not D.

This means that metal A is more reactive than metals B and C, while D is more reactive than A, so metal D is the most reactive

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3 years ago
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