Radioactive decay is a pseudo-first order reaction. When you know the half-life of the material, you could use this equation.
A= A₀(1/2)^t/h
where
A is the final activity
A₀ is the initial activity
t is the time
h is the half-life
A = (0.64)(1/2)^88/44 = <em>0.16 mbq</em>
It would be at 1 i believe because the heat you add after 0 degrees is then absorbed as potential energy instead of kinetic
Answer:
w/w means weight/weight
Therefore, in a 250 g of solution, 5% needs to be KCl,
i.e. 5% x 250 = 12.5 g of KCl is needed.
Answer: 4.05 mol O2, 15.36 mol H2O
Explanation:
I can answer each question individually if you post them individually.
2a. 3.24 mol NH3 * (5 mol O2 / 4 mol NH3) = 4.05 mol O2
2b. 12.8 mol O2 ( 6mol H2O/ 5 mol O2) = 15.36 mol H2O
Essentially what I did was dimensional analysis. Multiplying in a way that the units cancel out so the only thing remains is what each question asks for.
