A 2,294N force is applied to a 408kg mass. What is the acceleration of the mass?

Physics

1 answer:

Nataly_w [17]3 years ago

8 0

Answer:

5.622

Explanation:

a=F/M

a=2294/408

a=5.622

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1 year ago

3. A 40-gram ball of clay is dropped from a height, h, above a cup which is attached to a spring of spring force constant, k, of

zheka24 [161]

Answer:

the maximum speed of the ball is 12.65 m/s

Explanation:

Given;

mass of the ball, m = 40 g = 0.04 kg

spring constant, k = 25 N/m

Apply the principle of conservation of energy;

The Elastic potential energy of the spring will be converted into Kinetic of the ball;

$\frac{1}{2} kx^2 = \frac{1}{2} mv^2\\\\ kx^2 = mv^2\\\\v^2 = \frac{kx^2}{m} \\\\v = \sqrt{\frac{kx^2}{m}} \\\\v = \sqrt{\frac{(25)(0.506)^2}{0.04}} \\\\v = \sqrt{160.0225} \\\\v = 12.65 \ m/s$